A classic problem when learning C++ is checking what type of triangle you have based on 3 sides given by the user. Let's see how to write this logic cleanly using if-else structures without nesting too many conditions.
#include <iostream>
using namespace std;
int main() {
double a, b, c;
cout << "Enter three sides of the triangle: ";
cin >> a >> b >> c;
// Check if the sides can actually form a triangle
if (a + b > c && a + c > b && b + c > a) {
if (a == b && b == c) {
cout << "The triangle is Equilateral" << '\n';
}
else if (a == b || b == c || a == c) {
cout << "The triangle is Isosceles" << '\n';
}
else {
cout << "The triangle is Scalene" << '\n';
}
} else {
cout << "These sides cannot form a valid triangle" << '\n';
}
return 0;
}
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