(Redirected from Hot Springs Open Invitational)
| Tournament information | |
|---|---|
| Location | Hot Springs, Arkansas |
| Established | 1955 |
| Course | Hot Springs Country Club |
| Par | 72 |
| Tour | PGA Tour |
| Format | Stroke play |
| Prize fund | US$25,000 |
| Month played | July |
| Final year | 1963 |
| Tournament record score | |
| Aggregate | 270 Bo Wininger (1955) 270 Gene Littler (1959) |
| To par | −18 as above |
| Final champion | |
| 👁 United States Dave Hill | |
| Location map | |
Location in the United States 👁 Hot Springs CC is located in Arkansas Hot Springs CC Location in Arkansas | |
The Arlington Hotel Open was a PGA Tour event that was played from 1955 to 1963 at the Arlington golf course of the Hot Springs Country Club near the Arlington Hotel, now known as the Arlington Resort Hotel and Spa, a 484-room resort in the Ouachita Mountains of Hot Springs National Park in Arkansas.[1] The event was also known as the Hot Springs Open or Hot Springs Open Invitational. The Majestic Golf Course was constructed by Willie Park, Jnr. in 1898.[2] The Arlington Golf Course was designed and built by William Diddle in 1927.[3] Jimmy Demaret won the last of his 31 PGA Tour wins at this event in 1957.[4]
Winners
[edit]
References
[edit]- ^ "The Arlington Resort Hotel and Spa". Archived from the original on December 12, 2007. Retrieved November 18, 2007.
- ^ "The Arlington Golf Courses-Majestic". Archived from the original on July 24, 2007. Retrieved November 18, 2007.
- ^ "The Arlington Golf Courses-Arlington". Archived from the original on July 24, 2007. Retrieved November 18, 2007.
- ^ "The Year in Golf, 1957". Archived from the original on February 1, 2008. Retrieved November 18, 2007.
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