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Mathematical element

In commutative algebra, an element b of a commutative ring B is said to be integral over a subring A of B if b is a root of some monic polynomial over A.[1]

If A, B are fields, then the notions of "integral over" and of an "integral extension" are precisely "algebraic over" and "algebraic extensions" in field theory (since the root of any polynomial is the root of a monic polynomial).

The case of greatest interest in number theory is that of complex numbers integral over Z (e.g., πŸ‘ {\displaystyle {\sqrt {2}}}
or πŸ‘ {\displaystyle 1+i}
); in this context, the integral elements are usually called algebraic integers. The algebraic integers in a finite extension field k of the rationals Q form a subring of k, called the ring of integers of k, a central object of study in algebraic number theory.

In this article, the term ring will be understood to mean commutative ring with a multiplicative identity.

Definition

[edit]

Let πŸ‘ {\displaystyle B}
be a ring and let πŸ‘ {\displaystyle A\subset B}
be a subring of πŸ‘ {\displaystyle B.}
An element πŸ‘ {\displaystyle b}
of πŸ‘ {\displaystyle B}
is said to be integral over πŸ‘ {\displaystyle A}
if for some πŸ‘ {\displaystyle n\geq 1,}
there exists πŸ‘ {\displaystyle a_{0},\ a_{1},\ \dots ,\ a_{n-1}}
in πŸ‘ {\displaystyle A}
such that πŸ‘ {\displaystyle b^{n}+a_{n-1}b^{n-1}+\cdots +a_{1}b+a_{0}=0.}

The set of elements of πŸ‘ {\displaystyle B}
that are integral over πŸ‘ {\displaystyle A}
is called the integral closure of πŸ‘ {\displaystyle A}
in πŸ‘ {\displaystyle B.}
The integral closure of any subring πŸ‘ {\displaystyle A}
in πŸ‘ {\displaystyle B}
is, itself, a subring of πŸ‘ {\displaystyle B}
and contains πŸ‘ {\displaystyle A.}
If every element of πŸ‘ {\displaystyle B}
is integral over πŸ‘ {\displaystyle A,}
then we say that πŸ‘ {\displaystyle B}
is integral over πŸ‘ {\displaystyle A}
, or equivalently πŸ‘ {\displaystyle B}
is an integral extension of πŸ‘ {\displaystyle A.}

Examples

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Integral closure in algebraic number theory

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There are many examples of integral closure which can be found in algebraic number theory since it is fundamental for defining the ring of integers for an algebraic field extension πŸ‘ {\displaystyle K/\mathbb {Q} }
(or πŸ‘ {\displaystyle L/\mathbb {Q} _{p}}
).

Integral closure of integers in rationals

[edit]

Integers are the only elements of Q that are integral over Z. In other words, Z is the integral closure of Z in Q.

Quadratic extensions

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The Gaussian integers are the complex numbers of the form πŸ‘ {\displaystyle a+b{\sqrt {-1}},\,a,b\in \mathbf {Z} }
, and are integral over Z. πŸ‘ {\displaystyle \mathbf {Z} [{\sqrt {-1}}]}
is then the integral closure of Z in πŸ‘ {\displaystyle \mathbf {Q} ({\sqrt {-1}})}
. Typically this ring is denoted πŸ‘ {\displaystyle {\mathcal {O}}_{\mathbb {Q} [i]}}
.

The integral closure of Z in πŸ‘ {\displaystyle \mathbf {Q} ({\sqrt {5}})}
is the ring

πŸ‘ {\displaystyle {\mathcal {O}}_{\mathbb {Q} [{\sqrt {5}}]}=\mathbb {Z} \!\left[{\frac {1+{\sqrt {5}}}{2}}\right]}

This example and the previous one are examples of quadratic integers. The integral closure of a quadratic extension πŸ‘ {\displaystyle \mathbb {Q} ({\sqrt {d}})}
can be found by constructing the minimal polynomial of an arbitrary element πŸ‘ {\displaystyle a+b{\sqrt {d}}}
and finding number-theoretic criterion for the polynomial to have integral coefficients. This analysis can be found in the quadratic extensions article.

Roots of unity

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Let ΞΆ be a root of unity. Then the integral closure of Z in the cyclotomic field Q(ΞΆ) is Z[ΞΆ].[2] This can be found by using the minimal polynomial and using Eisenstein's criterion.

Ring of algebraic integers

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The integral closure of Z in the field of complex numbers C, or the algebraic closure πŸ‘ {\displaystyle {\overline {\mathbb {Q} }}}
is called the ring of algebraic integers.

Other

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The roots of unity, nilpotent elements and idempotent elements in any ring are integral over Z.

Integral closure in algebraic geometry

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In geometry, integral closure is closely related with normalization and normal schemes. It is the first step in resolution of singularities since it gives a process for resolving singularities of codimension 1.

  1. uβˆ’1 is integral over R if and only if uβˆ’1 ∈ R[u].
  2. πŸ‘ {\displaystyle R[u]\cap R[u^{-1}]}
    is integral over R.
  3. The integral closure of the homogeneous coordinate ring of a normal projective variety X is the ring of sections[4]
πŸ‘ {\displaystyle \bigoplus _{n\geq 0}\operatorname {H} ^{0}(X,{\mathcal {O}}_{X}(n)).}

Integrality in algebra

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Equivalent definitions

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Let B be a ring, and let A be a subring of B. Given an element b in B, the following conditions are equivalent:

(i) b is integral over A;
(ii) the subring A[b] of B generated by A and b is a finitely generated A-module;
(iii) there exists a subring C of B containing A[b] and which is a finitely generated A-module;
(iv) there exists a faithful A[b]-module M such that M is finitely generated as an A-module.

The usual proof of this uses the following variant of the Cayley–Hamilton theorem on determinants:

Theorem Let u be an endomorphism of an A-module M generated by n elements and I an ideal of A such that πŸ‘ {\displaystyle u(M)\subset IM}
. Then there is a relation:
πŸ‘ {\displaystyle u^{n}+a_{1}u^{n-1}+\cdots +a_{n-1}u+a_{n}=0,\,a_{i}\in I^{i}.}

This theorem (with I = A and u multiplication by b) gives (iv) β‡’ (i) and the rest is easy. Coincidentally, Nakayama's lemma is also an immediate consequence of this theorem.

Elementary properties

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Integral closure forms a ring

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It follows from the above four equivalent statements that the set of elements of πŸ‘ {\displaystyle B}
that are integral over πŸ‘ {\displaystyle A}
forms a subring of πŸ‘ {\displaystyle B}
containing πŸ‘ {\displaystyle A}
. (Proof: If x, y are elements of πŸ‘ {\displaystyle B}
that are integral over πŸ‘ {\displaystyle A}
, then πŸ‘ {\displaystyle x+y,xy,-x}
are integral over πŸ‘ {\displaystyle A}
since they stabilize πŸ‘ {\displaystyle A[x]A[y]}
, which is a finitely generated module over πŸ‘ {\displaystyle A}
and is annihilated only by zero.)[5] This ring is called the integral closure of πŸ‘ {\displaystyle A}
in πŸ‘ {\displaystyle B}
.

Transitivity of integrality

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Another consequence of the above equivalence is that "integrality" is transitive, in the following sense. Let πŸ‘ {\displaystyle C}
be a ring containing πŸ‘ {\displaystyle B}
and πŸ‘ {\displaystyle c\in C}
. If πŸ‘ {\displaystyle c}
is integral over πŸ‘ {\displaystyle B}
and πŸ‘ {\displaystyle B}
integral over πŸ‘ {\displaystyle A}
, then πŸ‘ {\displaystyle c}
is integral over πŸ‘ {\displaystyle A}
. In particular, if πŸ‘ {\displaystyle C}
is itself integral over πŸ‘ {\displaystyle B}
and πŸ‘ {\displaystyle B}
is integral over πŸ‘ {\displaystyle A}
, then πŸ‘ {\displaystyle C}
is also integral over πŸ‘ {\displaystyle A}
.

Integral closed in fraction field

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If πŸ‘ {\displaystyle A}
happens to be the integral closure of πŸ‘ {\displaystyle A}
in πŸ‘ {\displaystyle B}
, then A is said to be integrally closed in πŸ‘ {\displaystyle B}
. If πŸ‘ {\displaystyle B}
is the total ring of fractions of πŸ‘ {\displaystyle A}
, (e.g., the field of fractions when πŸ‘ {\displaystyle A}
is an integral domain), then one sometimes drops the qualification "in πŸ‘ {\displaystyle B}
" and simply says "integral closure of πŸ‘ {\displaystyle A}
" and "πŸ‘ {\displaystyle A}
is integrally closed."[6] For example, the ring of integers πŸ‘ {\displaystyle {\mathcal {O}}_{K}}
is integrally closed in the field πŸ‘ {\displaystyle K}
.

Transitivity of integral closure with integrally closed domains

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Let A be an integral domain with the field of fractions K and A' the integral closure of A in an algebraic field extension L of K. Then the field of fractions of A' is L. In particular, A' is an integrally closed domain.

Transitivity in algebraic number theory
[edit]

This situation is applicable in algebraic number theory when relating the ring of integers and a field extension. In particular, given a field extension πŸ‘ {\displaystyle L/K}
the integral closure of πŸ‘ {\displaystyle {\mathcal {O}}_{K}}
in πŸ‘ {\displaystyle L}
is the ring of integers πŸ‘ {\displaystyle {\mathcal {O}}_{L}}
.

Remarks

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Note that transitivity of integrality above implies that if πŸ‘ {\displaystyle B}
is integral over πŸ‘ {\displaystyle A}
, then πŸ‘ {\displaystyle B}
is a union (equivalently an inductive limit) of subrings that are finitely generated πŸ‘ {\displaystyle A}
-modules.

If πŸ‘ {\displaystyle A}
is noetherian, transitivity of integrality can be weakened to the statement:

There exists a finitely generated πŸ‘ {\displaystyle A}
-submodule of πŸ‘ {\displaystyle B}
that contains πŸ‘ {\displaystyle A[b]}
.

Relation with finiteness conditions

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Finally, the assumption that πŸ‘ {\displaystyle A}
be a subring of πŸ‘ {\displaystyle B}
can be modified a bit. If πŸ‘ {\displaystyle f:A\to B}
is a ring homomorphism, then one says πŸ‘ {\displaystyle f}
is integral if πŸ‘ {\displaystyle B}
is integral over πŸ‘ {\displaystyle f(A)}
. In the same way one says πŸ‘ {\displaystyle f}
is finite (πŸ‘ {\displaystyle B}
finitely generated πŸ‘ {\displaystyle A}
-module) or of finite type (πŸ‘ {\displaystyle B}
finitely generated πŸ‘ {\displaystyle A}
-algebra). In this viewpoint, one has that

πŸ‘ {\displaystyle f}
is finite if and only if πŸ‘ {\displaystyle f}
is integral and of finite type.

Or more explicitly,

πŸ‘ {\displaystyle B}
is a finitely generated πŸ‘ {\displaystyle A}
-module if and only if πŸ‘ {\displaystyle B}
is generated as an πŸ‘ {\displaystyle A}
-algebra by a finite number of elements integral over πŸ‘ {\displaystyle A}
.

Integral extensions

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Cohen-Seidenberg theorems

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An integral extension A βІ B has the going-up property, the lying over property, and the incomparability property (Cohen–Seidenberg theorems). Explicitly, given a chain of prime ideals πŸ‘ {\displaystyle {\mathfrak {p}}_{1}\subset \cdots \subset {\mathfrak {p}}_{n}}
in A there exists a πŸ‘ {\displaystyle {\mathfrak {p}}'_{1}\subset \cdots \subset {\mathfrak {p}}'_{n}}
in B with πŸ‘ {\displaystyle {\mathfrak {p}}_{i}={\mathfrak {p}}'_{i}\cap A}
(going-up and lying over) and two distinct prime ideals with inclusion relation cannot contract to the same prime ideal (incomparability). In particular, the Krull dimensions of A and B are the same. Furthermore, if A is an integrally closed domain, then the going-down holds (see below).

In general, the going-up implies the lying-over.[7] Thus, in the below, we simply say the "going-up" to mean "going-up" and "lying-over".

When A, B are domains such that B is integral over A, A is a field if and only if B is a field. As a corollary, one has: given a prime ideal πŸ‘ {\displaystyle {\mathfrak {q}}}
of B, πŸ‘ {\displaystyle {\mathfrak {q}}}
is a maximal ideal of B if and only if πŸ‘ {\displaystyle {\mathfrak {q}}\cap A}
is a maximal ideal of A. Another corollary: if L/K is an algebraic extension, then any subring of L containing K is a field.

Applications

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Let B be a ring that is integral over a subring A and k an algebraically closed field. If πŸ‘ {\displaystyle f:A\to k}
is a homomorphism, then f extends to a homomorphism B β†’ k.[8] This follows from the going-up.

Geometric interpretation of going-up

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Let πŸ‘ {\displaystyle f:A\to B}
be an integral extension of rings. Then the induced map

πŸ‘ {\displaystyle {\begin{cases}f^{\#}:\operatorname {Spec} B\to \operatorname {Spec} A\\p\mapsto f^{-1}(p)\end{cases}}}

is a closed map; in fact, πŸ‘ {\displaystyle f^{\#}(V(I))=V(f^{-1}(I))}
for any ideal I and πŸ‘ {\displaystyle f^{\#}}
is surjective if f is injective. This is a geometric interpretation of the going-up.

Geometric interpretation of integral extensions

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Let B be a ring and A a subring that is a noetherian integrally closed domain (i.e., πŸ‘ {\displaystyle \operatorname {Spec} A}
is a normal scheme). If B is integral over A, then πŸ‘ {\displaystyle \operatorname {Spec} B\to \operatorname {Spec} A}
is submersive; i.e., the topology of πŸ‘ {\displaystyle \operatorname {Spec} A}
is the quotient topology.[9] The proof uses the notion of constructible sets. (See also: Torsor (algebraic geometry).)

Integrality, base-change, universally-closed, and geometry

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If πŸ‘ {\displaystyle B}
is integral over πŸ‘ {\displaystyle A}
, then πŸ‘ {\displaystyle B\otimes _{A}R}
is integral over R for any A-algebra R.[10] In particular, πŸ‘ {\displaystyle \operatorname {Spec} (B\otimes _{A}R)\to \operatorname {Spec} R}
is closed; i.e., the integral extension induces a "universally closed" map. This leads to a . Namely, let B be a ring with only finitely many minimal prime ideals (e.g., integral domain or noetherian ring). Then B is integral over a (subring) A if and only if πŸ‘ {\displaystyle \operatorname {Spec} (B\otimes _{A}R)\to \operatorname {Spec} R}
is closed for any A-algebra R.[11] In particular, every proper map is universally closed.[12]

Galois actions on integral extensions of integrally closed domains

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Proposition. Let A be an integrally closed domain with the field of fractions K, L a finite normal extension of K, B the integral closure of A in L. Then the group πŸ‘ {\displaystyle G=\operatorname {Gal} (L/K)}
acts transitively on each fiber of πŸ‘ {\displaystyle \operatorname {Spec} B\to \operatorname {Spec} A}
.

Proof. Suppose πŸ‘ {\displaystyle {\mathfrak {p}}_{2}\neq \sigma ({\mathfrak {p}}_{1})}
for any πŸ‘ {\displaystyle \sigma }
in G. Then, by prime avoidance, there is an element x in πŸ‘ {\displaystyle {\mathfrak {p}}_{2}}
such that πŸ‘ {\displaystyle \sigma (x)\not \in {\mathfrak {p}}_{1}}
for any πŸ‘ {\displaystyle \sigma }
. G fixes the element πŸ‘ {\displaystyle y=\prod \nolimits _{\sigma }\sigma (x)}
and thus y is purely inseparable over K. Then some power πŸ‘ {\displaystyle y^{e}}
belongs to K; since A is integrally closed we have: πŸ‘ {\displaystyle y^{e}\in A.}
Thus, we found πŸ‘ {\displaystyle y^{e}}
is in πŸ‘ {\displaystyle {\mathfrak {p}}_{2}\cap A}
but not in πŸ‘ {\displaystyle {\mathfrak {p}}_{1}\cap A}
; i.e., πŸ‘ {\displaystyle {\mathfrak {p}}_{1}\cap A\neq {\mathfrak {p}}_{2}\cap A}
.

Application to algebraic number theory

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The Galois group πŸ‘ {\displaystyle \operatorname {Gal} (L/K)}
then acts on all of the prime ideals πŸ‘ {\displaystyle {\mathfrak {q}}_{1},\ldots ,{\mathfrak {q}}_{k}\in {\text{Spec}}({\mathcal {O}}_{L})}
lying over a fixed prime ideal πŸ‘ {\displaystyle {\mathfrak {p}}\in {\text{Spec}}({\mathcal {O}}_{K})}
.[13] That is, if

πŸ‘ {\displaystyle {\mathfrak {p}}={\mathfrak {q}}_{1}^{e_{1}}\cdots {\mathfrak {q}}_{k}^{e_{k}}\subset {\mathcal {O}}_{L}}

then there is a Galois action on the set πŸ‘ {\displaystyle S_{\mathfrak {p}}=\{{\mathfrak {q}}_{1},\ldots ,{\mathfrak {q}}_{k}\}}
. This is called the Splitting of prime ideals in Galois extensions.

Remarks

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The same idea in the proof shows that if πŸ‘ {\displaystyle L/K}
is a purely inseparable extension (need not be normal), then πŸ‘ {\displaystyle \operatorname {Spec} B\to \operatorname {Spec} A}
is bijective.

Let A, K, etc. as before but assume L is only a finite field extension of K. Then

(i) πŸ‘ {\displaystyle \operatorname {Spec} B\to \operatorname {Spec} A}
has finite fibers.
(ii) the going-down holds between A and B: given πŸ‘ {\displaystyle {\mathfrak {p}}_{1}\subset \cdots \subset {\mathfrak {p}}_{n}={\mathfrak {p}}'_{n}\cap A}
, there exists πŸ‘ {\displaystyle {\mathfrak {p}}'_{1}\subset \cdots \subset {\mathfrak {p}}'_{n}}
that contracts to it.

Indeed, in both statements, by enlarging L, we can assume L is a normal extension. Then (i) is immediate. As for (ii), by the going-up, we can find a chain πŸ‘ {\displaystyle {\mathfrak {p}}''_{i}}
that contracts to πŸ‘ {\displaystyle {\mathfrak {p}}'_{i}}
. By transitivity, there is πŸ‘ {\displaystyle \sigma \in G}
such that πŸ‘ {\displaystyle \sigma ({\mathfrak {p}}''_{n})={\mathfrak {p}}'_{n}}
and then πŸ‘ {\displaystyle {\mathfrak {p}}'_{i}=\sigma ({\mathfrak {p}}''_{i})}
are the desired chain.

Integral closure

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Let A βŠ‚ B be rings and A' the integral closure of A in B. (See above for the definition.)

Integral closures behave nicely under various constructions. Specifically, for a multiplicatively closed subset S of A, the localization Sβˆ’1A' is the integral closure of Sβˆ’1A in Sβˆ’1B, and πŸ‘ {\displaystyle A'[t]}
is the integral closure of πŸ‘ {\displaystyle A[t]}
in πŸ‘ {\displaystyle B[t]}
.[14] If πŸ‘ {\displaystyle A_{i}}
are subrings of rings πŸ‘ {\displaystyle B_{i},1\leq i\leq n}
, then the integral closure of πŸ‘ {\displaystyle \prod A_{i}}
in πŸ‘ {\displaystyle \prod B_{i}}
is πŸ‘ {\displaystyle \prod {A_{i}}'}
where πŸ‘ {\displaystyle {A_{i}}'}
are the integral closures of πŸ‘ {\displaystyle A_{i}}
in πŸ‘ {\displaystyle B_{i}}
.[15]

The integral closure of a local ring A in, say, B, need not be local. (If this is the case, the ring is called unibranch.) This is the case for example when A is Henselian and B is a field extension of the field of fractions of A.

If A is a subring of a field K, then the integral closure of A in K is the intersection of all valuation rings of K containing A.

Let A be an πŸ‘ {\displaystyle \mathbb {N} }
-graded subring of an πŸ‘ {\displaystyle \mathbb {N} }
-graded ring B. Then the integral closure of A in B is an πŸ‘ {\displaystyle \mathbb {N} }
-graded subring of B.[16]

There is also a concept of the integral closure of an ideal. The integral closure of an ideal πŸ‘ {\displaystyle I\subset R}
, usually denoted by πŸ‘ {\displaystyle {\overline {I}}}
, is the set of all elements πŸ‘ {\displaystyle r\in R}
such that there exists a monic polynomial

πŸ‘ {\displaystyle x^{n}+a_{1}x^{n-1}+\cdots +a_{n-1}x^{1}+a_{n}}

with πŸ‘ {\displaystyle a_{i}\in I^{i}}
with πŸ‘ {\displaystyle r}
as a root.[17][18] The radical of an ideal is integrally closed.[19][20]

For noetherian rings, there are alternate definitions as well.

The notion of integral closure of an ideal is used in some proofs of the going-down theorem.

Conductor

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Let B be a ring and A a subring of B such that B is integral over A. Then the annihilator of the A-module B/A is called the conductor of A in B. Because the notion has origin in algebraic number theory, the conductor is denoted by πŸ‘ {\displaystyle {\mathfrak {f}}={\mathfrak {f}}(B/A)}
. Explicitly, πŸ‘ {\displaystyle {\mathfrak {f}}}
consists of elements a in A such that πŸ‘ {\displaystyle aB\subset A}
. (cf. idealizer in abstract algebra.) It is the largest ideal of A that is also an ideal of B.[21] If S is a multiplicatively closed subset of A, then

πŸ‘ {\displaystyle S^{-1}{\mathfrak {f}}(B/A)={\mathfrak {f}}(S^{-1}B/S^{-1}A)}
.

If B is a subring of the total ring of fractions of A, then we may identify

πŸ‘ {\displaystyle {\mathfrak {f}}(B/A)=\operatorname {Hom} _{A}(B,A)}
.

Example: Let k be a field and let πŸ‘ {\displaystyle A=k[t^{2},t^{3}]\subset B=k[t]}
(i.e., A is the coordinate ring of the affine curve πŸ‘ {\displaystyle x^{2}=y^{3}}
). B is the integral closure of A in πŸ‘ {\displaystyle k(t)}
. The conductor of A in B is the ideal πŸ‘ {\displaystyle (t^{2},t^{3})A}
. More generally, the conductor of πŸ‘ {\displaystyle A=k[[t^{a},t^{b}]]}
, a, b relatively prime, is πŸ‘ {\displaystyle (t^{c},t^{c+1},\dots )A}
with πŸ‘ {\displaystyle c=(a-1)(b-1)}
.[22]

Suppose B is the integral closure of an integral domain A in the field of fractions of A such that the A-module πŸ‘ {\displaystyle B/A}
is finitely generated. Then the conductor πŸ‘ {\displaystyle {\mathfrak {f}}}
of A is an ideal defining the support of πŸ‘ {\displaystyle B/A}
; thus, A coincides with B in the complement of πŸ‘ {\displaystyle V({\mathfrak {f}})}
in πŸ‘ {\displaystyle \operatorname {Spec} A}
. In particular, the set πŸ‘ {\displaystyle \{{\mathfrak {p}}\in \operatorname {Spec} A\mid A_{\mathfrak {p}}{\text{ is integrally closed}}\}}
, the complement of πŸ‘ {\displaystyle V({\mathfrak {f}})}
, is an open set.

Finiteness of integral closure

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An important but difficult question is on the finiteness of the integral closure of a finitely generated algebra. There are several known results.

The integral closure of a Dedekind domain in a finite extension of the field of fractions is a Dedekind domain; in particular, a noetherian ring. This is a consequence of the Krull–Akizuki theorem. In general, the integral closure of a noetherian domain of dimension at most 2 is noetherian; Nagata gave an example of dimension 3 noetherian domain whose integral closure is not noetherian.[23] A nicer statement is this: the integral closure of a noetherian domain is a Krull domain (Mori–Nagata theorem). Nagata also gave an example of dimension 1 noetherian local domain such that the integral closure is not finite over that domain.[citation needed]

Let A be a noetherian integrally closed domain with field of fractions K. If L/K is a finite separable extension, then the integral closure πŸ‘ {\displaystyle A'}
of A in L is a finitely generated A-module.[24] This is easy and standard (uses the fact that the trace defines a non-degenerate bilinear form).

Let A be a finitely generated algebra over a field k that is an integral domain with field of fractions K. If L is a finite extension of K, then the integral closure πŸ‘ {\displaystyle A'}
of A in L is a finitely generated A-module and is also a finitely generated k-algebra.[25] The result is due to Noether and can be shown using the Noether normalization lemma as follows. It is clear that it is enough to show the assertion when L/K is either separable or purely inseparable. The separable case is noted above, so assume L/K is purely inseparable. By the normalization lemma, A is integral over the polynomial ring πŸ‘ {\displaystyle S=k[x_{1},...,x_{d}]}
. Since L/K is a finite purely inseparable extension, there is a power q of a prime number such that every element of L is a q-th root of an element in K. Let πŸ‘ {\displaystyle k'}
be a finite extension of k containing all q-th roots of coefficients of finitely many rational functions that generate L. Then we have: πŸ‘ {\displaystyle L\subset k'(x_{1}^{1/q},...,x_{d}^{1/q}).}
The ring on the right is the field of fractions of πŸ‘ {\displaystyle k'[x_{1}^{1/q},...,x_{d}^{1/q}]}
, which is the integral closure of S; thus, contains πŸ‘ {\displaystyle A'}
. Hence, πŸ‘ {\displaystyle A'}
is finite over S; a fortiori, over A. The result remains true if we replace k by Z.

The integral closure of a complete local noetherian domain A in a finite extension of the field of fractions of A is finite over A.[26] More precisely, for a local noetherian ring R, we have the following chains of implications:[27]

(i) A complete πŸ‘ {\displaystyle \Rightarrow }
A is a Nagata ring
(ii) A is a Nagata domain πŸ‘ {\displaystyle \Rightarrow }
A analytically unramified πŸ‘ {\displaystyle \Rightarrow }
the integral closure of the completion πŸ‘ {\displaystyle {\widehat {A}}}
is finite over πŸ‘ {\displaystyle {\widehat {A}}}
πŸ‘ {\displaystyle \Rightarrow }
the integral closure of A is finite over A.

The Grauert–Remmert–de Jong Criterion

[edit]

The Grauert–Remmert–de Jong criterion provides a necessary and sufficient condition for a ring to be normal.

The Criterion

[edit]

Let πŸ‘ {\displaystyle A}
be a reduced Noetherian domain and πŸ‘ {\displaystyle I\subset A}
be an ideal satisfying the following conditions:

  1. πŸ‘ {\displaystyle I}
    is a radical ideal (i.e., πŸ‘ {\displaystyle {\sqrt {I}}=I}
    ).
  2. The variety πŸ‘ {\displaystyle V(I)}
    contains the non-normal locus of πŸ‘ {\displaystyle I}
    (i.e., for every prime ideal πŸ‘ {\displaystyle P\in \operatorname {Spec} (A)}
    where the local ring πŸ‘ {\displaystyle A_{P}}
    is not normal, πŸ‘ {\displaystyle P\supseteq I}
    ).

Then: the ring πŸ‘ {\displaystyle A}
is normal if and only if the natural inclusion into the endomorphism ring of πŸ‘ {\displaystyle I}

πŸ‘ {\displaystyle \phi :A\hookrightarrow \operatorname {Hom} _{A}(I,I)}

is an isomorphism.

Algorithmic Application (The de Jong Algorithm)

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If πŸ‘ {\displaystyle A}
is not normal, the endomorphism ring πŸ‘ {\displaystyle S=\operatorname {Hom} _{A}(I,I)}
provides a strictly larger integral ring extension πŸ‘ {\displaystyle A\subsetneq S}
within the quotient field πŸ‘ {\displaystyle Q(A)}
.

[28]

The Grauert–Remmert–de Jong Criterion

[edit]

The Grauert–Remmert–de Jong criterion provides a necessary and sufficient condition for a ring to be normal.

The Criterion

[edit]

Let πŸ‘ {\displaystyle A}
be a reduced Noetherian domain and πŸ‘ {\displaystyle I\subset A}
be an ideal satisfying the following conditions:

  1. πŸ‘ {\displaystyle I}
    is a radical ideal (i.e., πŸ‘ {\displaystyle {\sqrt {I}}=I}
    ).
  2. The variety πŸ‘ {\displaystyle V(I)}
    contains the non-normal locus of πŸ‘ {\displaystyle I}
    (i.e., for every prime ideal πŸ‘ {\displaystyle P\in \operatorname {Spec} (A)}
    where the local ring πŸ‘ {\displaystyle A_{P}}
    is not normal, πŸ‘ {\displaystyle P\supseteq I}
    ).

Then: the ring πŸ‘ {\displaystyle A}
is normal if and only if the natural inclusion into the endomorphism ring of πŸ‘ {\displaystyle I}

πŸ‘ {\displaystyle \phi :A\hookrightarrow \operatorname {Hom} _{A}(I,I)}

is an isomorphism.

Algorithmic Application (The de Jong Algorithm)

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If πŸ‘ {\displaystyle A}
is not normal, the endomorphism ring πŸ‘ {\displaystyle S=\operatorname {Hom} _{A}(I,I)}
provides a strictly larger integral ring extension πŸ‘ {\displaystyle A\subsetneq S}
within the quotient field πŸ‘ {\displaystyle Q(A)}
.

[29]

Noether's normalization lemma

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Noether's normalisation lemma is a theorem in commutative algebra. Given a field K and a finitely generated K-algebra A, the theorem says it is possible to find elements y1, y2, ..., ym in A that are algebraically independent over K such that A is finite (and hence integral) over B = K[y1,..., ym]. Thus the extension K βŠ‚ A can be written as a composite K βŠ‚ B βŠ‚ A where K βŠ‚ B is a purely transcendental extension and B βŠ‚ A is finite.[30]

Integral morphisms

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In algebraic geometry, a morphism πŸ‘ {\displaystyle f:X\to Y}
of schemes is integral if it is affine and if for some (equivalently, every) affine open cover πŸ‘ {\displaystyle U_{i}}
of Y, every map πŸ‘ {\displaystyle f^{-1}(U_{i})\to U_{i}}
is of the form πŸ‘ {\displaystyle \operatorname {Spec} (A)\to \operatorname {Spec} (B)}
where A is an integral B-algebra. The class of integral morphisms is more general than the class of finite morphisms because there are integral extensions that are not finite, such as, in many cases, the algebraic closure of a field over the field.

Absolute integral closure

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Let A be an integral domain and L (some) algebraic closure of the field of fractions of A. Then the integral closure πŸ‘ {\displaystyle A^{+}}
of A in L is called the absolute integral closure of A.[31] It is unique up to a non-canonical isomorphism. The ring of all algebraic integers is an example (and thus πŸ‘ {\displaystyle A^{+}}
is typically not noetherian).

See also

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Notes

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  1. ^ The above equation is sometimes called an integral equation and b is said to be integrally dependent on A (as opposed to algebraic dependent).
  2. ^ Milne 2020, Theorem 6.4
  3. ^ Kaplansky 1974, 1.2. Exercise 4.
  4. ^ Hartshorne 1977, Ch. II, Exercise 5.14
  5. ^ This proof is due to Dedekind (Milne, ANT). Alternatively, one can use symmetric polynomials to show integral elements form a ring. (loc cit.)
  6. ^ Chapter 2 of Huneke & Swanson 2006
  7. ^ Kaplansky 1974, Theorem 42
  8. ^ Bourbaki 2006, Ch 5, Β§2, Corollary 4 to Theorem 1.
  9. ^ Matsumura 1970, Ch 2. Theorem 7
  10. ^ Bourbaki 2006, Ch 5, Β§1, Proposition 5
  11. ^ Atiyah & Macdonald 1994, Ch 5. Exercise 35
  12. ^ "Section 32.14 (05JW): Universally closed morphismsβ€”The Stacks project". stacks.math.columbia.edu. Retrieved 2020-05-11.
  13. ^ Stein. Computational Introduction to Algebraic Number Theory (PDF). p. 101.
  14. ^ An exercise in Atiyah & Macdonald 1994
  15. ^ Bourbaki 2006, Ch 5, Β§1, Proposition 9
  16. ^ Proof: Let πŸ‘ {\displaystyle \phi :B\to B[t]}
    be a ring homomorphism such that πŸ‘ {\displaystyle \phi (b_{n})=b_{n}t^{n}}
    if πŸ‘ {\displaystyle b_{n}}
    is homogeneous of degree n. The integral closure of πŸ‘ {\displaystyle A[t]}
    in πŸ‘ {\displaystyle B[t]}
    is πŸ‘ {\displaystyle A'[t]}
    , where πŸ‘ {\displaystyle A'}
    is the integral closure of A in B. If b in B is integral over A, then πŸ‘ {\displaystyle \phi (b)}
    is integral over πŸ‘ {\displaystyle A[t]}
    ; i.e., it is in πŸ‘ {\displaystyle A'[t]}
    . That is, each coefficient πŸ‘ {\displaystyle b_{n}}
    in the polynomial πŸ‘ {\displaystyle \phi (b)}
    is in A.
  17. ^ Exercise 4.14 in Eisenbud 1995
  18. ^ Definition 1.1.1 in Huneke & Swanson 2006
  19. ^ Exercise 4.15 in Eisenbud 1995
  20. ^ Remark 1.1.3 in Huneke & Swanson 2006
  21. ^ Chapter 12 of Huneke & Swanson 2006
  22. ^ Huneke & Swanson 2006, Example 12.2.1
  23. ^ Huneke & Swanson 2006, Exercise 4.9
  24. ^ Atiyah & Macdonald 1994, Ch 5. Proposition 5.17
  25. ^ Hartshorne 1977, Ch I. Theorem 3.9 A
  26. ^ Huneke & Swanson 2006, Theorem 4.3.4
  27. ^ Matsumura 1970, Ch 12
  28. ^ de Jong, Theo (1998). "An algorithm for computing the integral closure". Journal of Symbolic Computation. 26 (3): 273–277. doi:10.1006/jsco.1998.0216.
  29. ^ de Jong, Theo (1998). "An algorithm for computing the integral closure". Journal of Symbolic Computation. 26 (3): 273–277. doi:10.1006/jsco.1998.0216.
  30. ^ Chapter 4 of Reid.
  31. ^ Melvin Hochster, Math 711: Lecture of September 7, 2007

References

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Further reading

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