Note
Access to this page requires authorization. You can try signing in or .
Access to this page requires authorization. You can try .
OrderablePartitioner<TSource>.GetDynamicPartitions Method
Definition
- Namespace:
- System.Collections.Concurrent
- Assemblies:
- mscorlib.dll, System.Collections.Concurrent.dll
- Assemblies:
- netstandard.dll, System.Collections.Concurrent.dll
- Assembly:
- System.Collections.Concurrent.dll
- Assembly:
- mscorlib.dll
- Assembly:
- netstandard.dll
- Source:
- OrderablePartitioner.cs
- Source:
- OrderablePartitioner.cs
- Source:
- OrderablePartitioner.cs
- Source:
- OrderablePartitioner.cs
- Source:
- OrderablePartitioner.cs
Important
Some information relates to prerelease product that may be substantially modified before itβs released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Creates an object that can partition the underlying collection into a variable number of partitions.
public:
override System::Collections::Generic::IEnumerable<TSource> ^ GetDynamicPartitions();
public override System.Collections.Generic.IEnumerable<TSource> GetDynamicPartitions();
override this.GetDynamicPartitions : unit -> seq<'Source>
Public Overrides Function GetDynamicPartitions () As IEnumerable(Of TSource)
Returns
An object that can create partitions over the underlying data source.
Exceptions
Dynamic partitioning is not supported by the base class. It must be implemented in derived classes.
Remarks
The returned object implements the System.Collections.Generic.IEnumerable<T> interface. Calling GetEnumerator on the object creates another partition over the sequence.
The default implementation provides the same behavior as GetOrderableDynamicPartitions except that the returned set of partitions does not provide the keys for the elements.
The GetDynamicPartitions method is only supported if the SupportsDynamicPartitions property returns true.
For more information, see Custom Partitioners for PLINQ and TPL.
Applies to
See also
Feedback
Was this page helpful?
