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Math.Exp(Double) Method

Definition

Namespace:
System
Assemblies:
mscorlib.dll, System.Runtime.Extensions.dll
Assemblies:
netstandard.dll, System.Runtime.dll
Assembly:
System.Runtime.Extensions.dll
Assembly:
mscorlib.dll
Assembly:
netstandard.dll
Source:
Math.cs
Source:
Math.cs
Source:
Math.cs
Source:
Math.cs
Source:
Math.cs

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Returns e raised to the specified power.

public:
 static double Exp(double d);
public static double Exp(double d);
static member Exp : double -> double
Public Shared Function Exp (d As Double) As Double

Parameters

d
Double

A number specifying a power.

Returns

The number e raised to the power d. If d equals NaN or PositiveInfinity, that value is returned. If d equals NegativeInfinity, 0 is returned.

Examples

The following example uses Exp to evaluate certain exponential and logarithmic identities for selected values.

// Example for the Math.Exp( double ) method.
using System;

class ExpDemo
{
 public static void Main()
 {
 Console.WriteLine(
 "This example of Math.Exp( double ) " +
 "generates the following output.\n" );
 Console.WriteLine(
 "Evaluate [e ^ ln(X) == ln(e ^ X) == X] " +
 "with selected values for X:" );

 UseLnExp(0.1);
 UseLnExp(1.2);
 UseLnExp(4.9);
 UseLnExp(9.9);

 Console.WriteLine(
 "\nEvaluate these identities with " +
 "selected values for X and Y:" );
 Console.WriteLine( " (e ^ X) * (e ^ Y) == e ^ (X + Y)" );
 Console.WriteLine( " (e ^ X) ^ Y == e ^ (X * Y)" );
 Console.WriteLine( " X ^ Y == e ^ (Y * ln(X))" );

 UseTwoArgs(0.1, 1.2);
 UseTwoArgs(1.2, 4.9);
 UseTwoArgs(4.9, 9.9);
 }

 // Evaluate logarithmic/exponential identity with a given argument.
 static void UseLnExp(double arg)
 {
 // Evaluate e ^ ln(X) == ln(e ^ X) == X.
 Console.WriteLine(
 "\n Math.Exp(Math.Log({0})) == {1:E16}\n" +
 " Math.Log(Math.Exp({0})) == {2:E16}",
 arg, Math.Exp(Math.Log(arg)), Math.Log(Math.Exp(arg)) );
 }

 // Evaluate exponential identities that are functions of two arguments.
 static void UseTwoArgs(double argX, double argY)
 {
 // Evaluate (e ^ X) * (e ^ Y) == e ^ (X + Y).
 Console.WriteLine(
 "\nMath.Exp({0}) * Math.Exp({1}) == {2:E16}" +
 "\n Math.Exp({0} + {1}) == {3:E16}",
 argX, argY, Math.Exp(argX) * Math.Exp(argY),
 Math.Exp(argX + argY) );

 // Evaluate (e ^ X) ^ Y == e ^ (X * Y).
 Console.WriteLine(
 " Math.Pow(Math.Exp({0}), {1}) == {2:E16}" +
 "\n Math.Exp({0} * {1}) == {3:E16}",
 argX, argY, Math.Pow(Math.Exp(argX), argY),
 Math.Exp(argX * argY) );

 // Evaluate X ^ Y == e ^ (Y * ln(X)).
 Console.WriteLine(
 " Math.Pow({0}, {1}) == {2:E16}" +
 "\nMath.Exp({1} * Math.Log({0})) == {3:E16}",
 argX, argY, Math.Pow(argX, argY),
 Math.Exp(argY * Math.Log(argX)) );
 }
}

/*
This example of Math.Exp( double ) generates the following output.

Evaluate [e ^ ln(X) == ln(e ^ X) == X] with selected values for X:

 Math.Exp(Math.Log(0.1)) == 1.0000000000000001E-001
 Math.Log(Math.Exp(0.1)) == 1.0000000000000008E-001

 Math.Exp(Math.Log(1.2)) == 1.2000000000000000E+000
 Math.Log(Math.Exp(1.2)) == 1.2000000000000000E+000

 Math.Exp(Math.Log(4.9)) == 4.9000000000000012E+000
 Math.Log(Math.Exp(4.9)) == 4.9000000000000004E+000

 Math.Exp(Math.Log(9.9)) == 9.9000000000000004E+000
 Math.Log(Math.Exp(9.9)) == 9.9000000000000004E+000

Evaluate these identities with selected values for X and Y:
 (e ^ X) * (e ^ Y) == e ^ (X + Y)
 (e ^ X) ^ Y == e ^ (X * Y)
 X ^ Y == e ^ (Y * ln(X))

Math.Exp(0.1) * Math.Exp(1.2) == 3.6692966676192444E+000
 Math.Exp(0.1 + 1.2) == 3.6692966676192444E+000
 Math.Pow(Math.Exp(0.1), 1.2) == 1.1274968515793757E+000
 Math.Exp(0.1 * 1.2) == 1.1274968515793757E+000
 Math.Pow(0.1, 1.2) == 6.3095734448019331E-002
Math.Exp(1.2 * Math.Log(0.1)) == 6.3095734448019344E-002

Math.Exp(1.2) * Math.Exp(4.9) == 4.4585777008251705E+002
 Math.Exp(1.2 + 4.9) == 4.4585777008251716E+002
 Math.Pow(Math.Exp(1.2), 4.9) == 3.5780924170885260E+002
 Math.Exp(1.2 * 4.9) == 3.5780924170885277E+002
 Math.Pow(1.2, 4.9) == 2.4433636334442981E+000
Math.Exp(4.9 * Math.Log(1.2)) == 2.4433636334442981E+000

Math.Exp(4.9) * Math.Exp(9.9) == 2.6764450551890982E+006
 Math.Exp(4.9 + 9.9) == 2.6764450551891015E+006
 Math.Pow(Math.Exp(4.9), 9.9) == 1.1684908531676833E+021
 Math.Exp(4.9 * 9.9) == 1.1684908531676829E+021
 Math.Pow(4.9, 9.9) == 6.8067718210957060E+006
Math.Exp(9.9 * Math.Log(4.9)) == 6.8067718210956985E+006
*/
// Example for the Math.Exp( double ) method.
// The exp function may be used instead.

open System
printfn "This example of Math.Exp( double ) generates the following output.\n"
printfn "Evaluate [e ^ ln(X) = ln(e ^ X) = X] with selected values for X:"

// Evaluate logarithmic/exponential identity with a given argument.
let useLnExp arg =
 // Evaluate e ^ ln(X) = ln(e ^ X) = X.
 printfn $"\n Math.Exp(Math.Log({arg})) = {Math.Exp(Math.Log arg):E16}\n Math.Log(Math.Exp({arg})) = {Math.Log(Math.Exp arg):E16}"

// Evaluate exponential identities that are functions of two arguments.
let useTwoArgs argX argY =
 // Evaluate (e ^ X) * (e ^ Y) = e ^ (X + Y).
 printfn $"""
Math.Exp({argX}) * Math.Exp({argY}) = {Math.Exp argX * Math.Exp argY:E16}" +
 Math.Exp({argX} + {argY}) = {Math.Exp(argX + argY):E16}"""

 // Evaluate (e ^ X) ^ Y = e ^ (X * Y).
 printfn $" Math.Pow(Math.Exp({argX}), {argY}) = {Math.Pow(Math.Exp argX, argY):E16}\n Math.Exp({argX} * {argY}) = {Math.Exp(argX * argY):E16}"

 // Evaluate X ^ Y = e ^ (Y * ln(X)).
 printfn $" Math.Pow({argX}, {argY}) = {Math.Pow(argX, argY):E16}\nMath.Exp({argY} * Math.Log({argX})) = {Math.Exp(argY * Math.Log argX):E16}"

useLnExp 0.1
useLnExp 1.2
useLnExp 4.9
useLnExp 9.9

printfn "\nEvaluate these identities with selected values for X and Y:"
printfn " (e ^ X) * (e ^ Y) = e ^ (X + Y)"
printfn " (e ^ X) ^ Y = e ^ (X * Y)"
printfn " X ^ Y = e ^ (Y * ln(X))"

useTwoArgs 0.1 1.2
useTwoArgs 1.2 4.9
useTwoArgs 4.9 9.9

// This example of Math.Exp( double ) generates the following output.
//
// Evaluate [e ^ ln(X) = ln(e ^ X) = X] with selected values for X:
//
// Math.Exp(Math.Log(0.1)) = 1.0000000000000001E-001
// Math.Log(Math.Exp(0.1)) = 1.0000000000000008E-001
//
// Math.Exp(Math.Log(1.2)) = 1.2000000000000000E+000
// Math.Log(Math.Exp(1.2)) = 1.2000000000000000E+000
//
// Math.Exp(Math.Log(4.9)) = 4.9000000000000012E+000
// Math.Log(Math.Exp(4.9)) = 4.9000000000000004E+000
//
// Math.Exp(Math.Log(9.9)) = 9.9000000000000004E+000
// Math.Log(Math.Exp(9.9)) = 9.9000000000000004E+000
//
// Evaluate these identities with selected values for X and Y:
// (e ^ X) * (e ^ Y) = e ^ (X + Y)
// (e ^ X) ^ Y = e ^ (X * Y)
// X ^ Y = e ^ (Y * ln(X))
//
// Math.Exp(0.1) * Math.Exp(1.2) = 3.6692966676192444E+000
// Math.Exp(0.1 + 1.2) = 3.6692966676192444E+000
// Math.Pow(Math.Exp(0.1), 1.2) = 1.1274968515793757E+000
// Math.Exp(0.1 * 1.2) = 1.1274968515793757E+000
// Math.Pow(0.1, 1.2) = 6.3095734448019331E-002
// Math.Exp(1.2 * Math.Log(0.1)) = 6.3095734448019344E-002
//
// Math.Exp(1.2) * Math.Exp(4.9) = 4.4585777008251705E+002
// Math.Exp(1.2 + 4.9) = 4.4585777008251716E+002
// Math.Pow(Math.Exp(1.2), 4.9) = 3.5780924170885260E+002
// Math.Exp(1.2 * 4.9) = 3.5780924170885277E+002
// Math.Pow(1.2, 4.9) = 2.4433636334442981E+000
// Math.Exp(4.9 * Math.Log(1.2)) = 2.4433636334442981E+000
//
// Math.Exp(4.9) * Math.Exp(9.9) = 2.6764450551890982E+006
// Math.Exp(4.9 + 9.9) = 2.6764450551891015E+006
// Math.Pow(Math.Exp(4.9), 9.9) = 1.1684908531676833E+021
// Math.Exp(4.9 * 9.9) = 1.1684908531676829E+021
// Math.Pow(4.9, 9.9) = 6.8067718210957060E+006
// Math.Exp(9.9 * Math.Log(4.9)) = 6.8067718210956985E+006
' Example for the Math.Exp( Double ) method.
Module ExpDemo
 
 Sub Main()
 Console.WriteLine( _
 "This example of Math.Exp( Double ) " & _
 "generates the following output." & vbCrLf)
 Console.WriteLine( _
 "Evaluate [e ^ ln(X) == ln(e ^ X) == X] " & _
 "with selected values for X:")

 UseLnExp(0.1)
 UseLnExp(1.2)
 UseLnExp(4.9)
 UseLnExp(9.9)
 
 Console.WriteLine( vbCrLf & _
 "Evaluate these identities with selected values for X and Y:")
 Console.WriteLine(" (e ^ X) * (e ^ Y) = e ^ (X + Y)")
 Console.WriteLine(" (e ^ X) ^ Y = e ^ (X * Y)")
 Console.WriteLine(" X ^ Y = e ^ (Y * ln(X))")
 
 UseTwoArgs(0.1, 1.2)
 UseTwoArgs(1.2, 4.9)
 UseTwoArgs(4.9, 9.9)
 End Sub
 
 ' Evaluate logarithmic/exponential identity with a given argument.
 Sub UseLnExp(arg As Double)

 ' Evaluate e ^ ln(X) = ln(e ^ X) = X.
 Console.WriteLine( _
 vbCrLf & " Math.Exp(Math.Log({0})) = {1:E16}" + _
 vbCrLf & " Math.Log(Math.Exp({0})) = {2:E16}", _
 arg, Math.Exp(Math.Log(arg)), Math.Log(Math.Exp(arg)))
 End Sub
 
 ' Evaluate exponential identities that are functions of two arguments.
 Sub UseTwoArgs(argX As Double, argY As Double)

 ' Evaluate (e ^ X) * (e ^ Y) = e ^ (X + Y).
 Console.WriteLine( _
 vbCrLf & "Math.Exp({0}) * Math.Exp({1}) = {2:E16}" + _
 vbCrLf & " Math.Exp({0} + {1}) = {3:E16}", _
 argX, argY, Math.Exp(argX) * Math.Exp(argY), _
 Math.Exp((argX + argY)))
 
 ' Evaluate (e ^ X) ^ Y = e ^ (X * Y).
 Console.WriteLine( _
 " Math.Pow(Math.Exp({0}), {1}) = {2:E16}" + _
 vbCrLf & " Math.Exp({0} * {1}) = {3:E16}", _
 argX, argY, Math.Pow(Math.Exp(argX), argY), _
 Math.Exp((argX * argY)))
 
 ' Evaluate X ^ Y = e ^ (Y * ln(X)).
 Console.WriteLine( _
 " Math.Pow({0}, {1}) = {2:E16}" + _
 vbCrLf & "Math.Exp({1} * Math.Log({0})) = {3:E16}", _
 argX, argY, Math.Pow(argX, argY), _
 Math.Exp((argY * Math.Log(argX))))

 End Sub
End Module 'ExpDemo

' This example of Math.Exp( Double ) generates the following output.
' 
' Evaluate [e ^ ln(X) == ln(e ^ X) == X] with selected values for X:
' 
' Math.Exp(Math.Log(0.1)) = 1.0000000000000001E-001
' Math.Log(Math.Exp(0.1)) = 1.0000000000000008E-001
' 
' Math.Exp(Math.Log(1.2)) = 1.2000000000000000E+000
' Math.Log(Math.Exp(1.2)) = 1.2000000000000000E+000
' 
' Math.Exp(Math.Log(4.9)) = 4.9000000000000012E+000
' Math.Log(Math.Exp(4.9)) = 4.9000000000000004E+000
' 
' Math.Exp(Math.Log(9.9)) = 9.9000000000000004E+000
' Math.Log(Math.Exp(9.9)) = 9.9000000000000004E+000
' 
' Evaluate these identities with selected values for X and Y:
' (e ^ X) * (e ^ Y) = e ^ (X + Y)
' (e ^ X) ^ Y = e ^ (X * Y)
' X ^ Y = e ^ (Y * ln(X))
' 
' Math.Exp(0.1) * Math.Exp(1.2) = 3.6692966676192444E+000
' Math.Exp(0.1 + 1.2) = 3.6692966676192444E+000
' Math.Pow(Math.Exp(0.1), 1.2) = 1.1274968515793757E+000
' Math.Exp(0.1 * 1.2) = 1.1274968515793757E+000
' Math.Pow(0.1, 1.2) = 6.3095734448019331E-002
' Math.Exp(1.2 * Math.Log(0.1)) = 6.3095734448019344E-002
' 
' Math.Exp(1.2) * Math.Exp(4.9) = 4.4585777008251705E+002
' Math.Exp(1.2 + 4.9) = 4.4585777008251716E+002
' Math.Pow(Math.Exp(1.2), 4.9) = 3.5780924170885260E+002
' Math.Exp(1.2 * 4.9) = 3.5780924170885277E+002
' Math.Pow(1.2, 4.9) = 2.4433636334442981E+000
' Math.Exp(4.9 * Math.Log(1.2)) = 2.4433636334442981E+000
' 
' Math.Exp(4.9) * Math.Exp(9.9) = 2.6764450551890982E+006
' Math.Exp(4.9 + 9.9) = 2.6764450551891015E+006
' Math.Pow(Math.Exp(4.9), 9.9) = 1.1684908531676833E+021
' Math.Exp(4.9 * 9.9) = 1.1684908531676829E+021
' Math.Pow(4.9, 9.9) = 6.8067718210957060E+006
' Math.Exp(9.9 * Math.Log(4.9)) = 6.8067718210956985E+006

Remarks

e is a mathematical constant whose value is approximately 2.71828.

Use the Pow method to calculate powers of other bases.

Exp is the inverse of Log.

This method calls into the underlying C runtime, and the exact result or valid input range may differ between different operating systems or architectures.

Applies to

See also


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