XContainer.Nodes Method

public:
 System::Collections::Generic::IEnumerable<System::Xml::Linq::XNode ^> ^ Nodes();

public System.Collections.Generic.IEnumerable<System.Xml.Linq.XNode> Nodes();

member this.Nodes : unit -> seq<System.Xml.Linq.XNode>

Public Function Nodes () As IEnumerable(Of XNode)

Public Iterator Function Nodes () As IEnumerable(Of XNode)

Returns

An IEnumerable<T> of XNode containing the contents of this XContainer, in document order.

Examples

The following example creates an XML tree with a variety of types of nodes. It then queries this axis method to enumerate and print the nodes.

XElement xmlTree = new XElement("Root",
 new XElement("Child1", 1),
 new XElement("Child2", 2),
 new XComment("a comment"),
 new XElement("Child3", 3),
 new XElement("Child4", 4),
 new XText("mixed content"),
 new XElement("Child5", 5)
);
IEnumerable<XNode> nodes =
 from nd in xmlTree.Nodes()
 select nd;
foreach (XNode node in nodes)
 Console.WriteLine(node);

Dim xmlTree As XElement = _
 <Root>
 <Child1>1</Child1>
 <Child2>2</Child2>
 <!--a comment-->
 <Child3>3</Child3>
 <Child4>4</Child4>mixed content<Child5>5</Child5>
 </Root>

Dim nodes = From nd In xmlTree.Nodes() _
 Select nd

For Each node In nodes
 Console.WriteLine(node)
Next

This example produces the following output:

<Child1>1</Child1>
<Child2>2</Child2>
<!--a comment-->
<Child3>3</Child3>
<Child4>4</Child4>
mixed content
<Child5>5</Child5>

The following example creates an XML tree that contains a variety of types of nodes. It then enumerates through portions of the tree, printing the node types.

XDocument xmlTree = new XDocument(
 new XComment("a comment"),
 new XProcessingInstruction("xml-stylesheet", "type=\"text/xsl\" href=\"hello.xsl\""),
 new XElement("Root",
 new XAttribute("Att", "attContent"),
 new XElement("Child1",
 new XCData("CDATA content")
 ),
 new XElement("Child2",
 new XText("Text content")
 )
 )
);

foreach (XNode node in xmlTree.Nodes())
{
 Console.WriteLine(node.NodeType);
 if (node.NodeType == XmlNodeType.Element)
 {
 foreach (XAttribute att in ((XElement)node).Attributes())
 Console.WriteLine(att.NodeType);
 foreach (XNode node2 in ((XElement)node).Nodes())
 {
 Console.WriteLine(node2.NodeType);
 if (node2.NodeType == XmlNodeType.Element)
 foreach (XNode node3 in ((XElement)node2).Nodes())
 Console.WriteLine(node3.NodeType);
 }
 }
}

Dim xmlTree As XDocument = _
 <?xml version="1.0" encoding="utf-8"?>
 <!--a comment-->
 <?xml-stylesheet type='text/xsl' href='hello.xsl'?>
 <Root Att="attContent">
 <Child1><![CDATA[CDATA content]]></Child1>
 <Child2>Text content</Child2>
 </Root>

' Note that XNode uses XmlNodeType, which is in the System.Xml namespace
For Each node In xmlTree.Nodes
 Console.WriteLine(node.NodeType.ToString())
 If node.NodeType = XmlNodeType.Element Then
 For Each att In DirectCast(node, XElement).Attributes
 Console.WriteLine(att.NodeType.ToString())
 Next
 For Each node2 In DirectCast (node, XElement).Nodes()
 Console.WriteLine(node2.NodeType.ToString())
 If node2.NodeType = XmlNodeType.Element Then
 For Each node3 In DirectCast (node2, XElement).Nodes
 Console.WriteLine(node3.NodeType.ToString())
 Next
 End If
 Next
 End If
Next

This example produces the following output:

Comment
ProcessingInstruction
Element
Attribute
Element
CDATA
Element
Text

Remarks

Note that the content does not include attributes. In LINQ to XML, attributes are not considered to be nodes of the tree. They are name/value pairs associated with an element.

This method uses deferred execution.

See also

• Attributes()
• Descendants
• DescendantNodes()
• LINQ to XML overview