a(2) = 6 corresponds to
..O.X.X.......X.X.O.......O.X.X.......X.O.X.......X.O.X.......X.X.O
.X.X.O.X.....X.O.X.X.....X.X.X.O.....X.X.X.O.....O.X.X.X.....O.X.X.X
X.X.X.X.O...O.X.X.X.X...X.O.X.X.X...O.X.X.X.X...X.X.X.X.O...X.X.X.O.X
.O.X.X.X.....X.X.X.O.....X.X.X.O.....X.O.X.X.....X.X.O.X.....O.X.X.X
..X.O.X.......X.O.X.......O.X.X.......X.X.O.......O.X.X.......X.X.O
The bijection with a pair of the 3 X (2n+1) zero-sum arrays:
n=1, a(1)=2 corresponds to
3 4 2 3 2 4
and mirror image 4 2 3 2 4 3
element 2 3 4 -(2n+1) --> -1 0 1
position, left element 3 1 2 -( n+1) --> 1 -1 0
position in mirror 2 3 1 -( n+1) --> 0 1 -1
------- -------
sum of column 7 7 7 -(4n+3) 0 0 0
Swapping rows 2,3 yields the other 3 X 3 zero sum array.
n=2, a(2)=6 an example and its mirror, so 2 of the 6 solutions:
5 6 7 3 4 5 3 6 4 7
mirror image 7 4 6 3 5 4 3 7 6 5
3 4 5 6 7 -(2n+1) --> -2 -1 0 1 2
4 5 1 2 3 -( n+1) --> 1 2 -2 -1 0
4 2 5 3 1 -( n+1) --> 1 -1 2 0 -2
-------------- --------------
11 11 11 11 11 -(4n+3) --> 0 0 0 0 0
Swapping rows 2,3 yields the other 3 X 5 zero sum array.