Differentiating n times the Lambert function W(x) = Sum_{n>=1} n^(n-1)*x^n/n! with respect to x yields (d/dx)^n W(x) = exp(n*W(x))/(1-W(x))^n*R(n,1/(1-W(x))), where R(n,x) is the n-th row polynomial of this triangle. The first few values are R(1,x) = 1, R(2,x) = 1+x, R(3,x) = 2+4*x+3*x^2. The Ramanujan polynomials R(n,x) are strongly x-log-convex [Chen et al.].
Shor and Dumont-Ramamonjisoa have proved independently that the coefficient of x^k in R(n,x) counts rooted labeled trees on n vertices with k improper edges. Drake, Example 1.7.3, gives another combinatorial interpretation for this triangle as counting a family of labeled trees.
E.g.f.: series reversion with respect to x of (1-t+(t-1+x*t)*exp(-x)) = x + (1+t)*x^2/2! + (2+4*t+3*t^2)*x^3/3! + ....
The sequence of shifted row polynomials {p_n(1+t)}n>=1 begins [1,2+t,9+10*t+3*t^2,...]. These are the row polynomials of A048160.
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Let f(x) = exp(x)/(1-t*x). The e.g.f. A(x,t) = x + (1+t)*x^2/2! + (2+4*t+3*t^2)*x^3/3! + ... satisfies the autonomous differential equation dA/dx = f(A). The n-th row polynomial (n>=1) equals D^(n-1)(f(x)) evaluated at x = 0, where D is the operator f(x)*d/dx (apply [Dominici, Theorem 4.1]). - Peter Bala, Nov 09 2011
The polynomials (1+t)^(n-1)*p_n(1/(1+t)) are (up to sign) the row polynomials of A042977. - Peter Bala, Jul 23 2012
Let q_n = Sum_{k>=0} a(n,k)*t^(n-k), with q_0 = 1. (So q_1=t, q_2 = t+t^2, and q_3 = 3*t + 4*t^2 + 2*t^3.) Then Sum_{n>=0} q_n*x^n/n! = t - W((t-1-t^2*x)*exp(t-1)), where W is the Lambert function. - Ira M. Gessel, Jan 06 2012
