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A060801
Invert transform of odd numbers: a(n) = Sum_{k=1..n} (2*k+1)*a(n-k), a(0)=1.
7
1, 3, 14, 64, 292, 1332, 6076, 27716, 126428, 576708, 2630684, 12000004, 54738652, 249693252, 1138988956, 5195558276, 23699813468, 108107950788, 493140127004, 2249484733444, 10261143413212, 46806747599172, 213511451169436
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OFFSET
0,2
COMMENTS
a(n) is the number of generalized compositions of n when there are 2*i+1 different types of i, (i=1,2,...). -
Milan Janjic
, Sep 24 2010
LINKS
Colin Barker,
Table of n, a(n) for n = 0..1000
Daniel Birmajer, Juan B. Gil, and Michael D. Weiner,
(an + b)-color compositions
, arXiv:1707.07798 [math.CO], 2017.
Stéphane Ouvry and Alexios P. Polychronakos,
Signed area enumeration for lattice walks
, Séminaire Lotharingien de Combinatoire (2023) Vol. 87B.
N. J. A. Sloane,
Transforms
Index entries for linear recurrences with constant coefficients
, signature (5,-2).
FORMULA
G.f.: (x^2-2*x+1)/(2*x^2-5*x+1).
G.f.: 1 / (1 - 3*x - 5*x^2 - 7*x^3 - 9*x^4 - 11*x^5 - ...). -
Gary W. Adamson
, Jul 27 2009
a(n) = 5*a(n-1) - 2*a(n-2) with a(1) = 3, a(2) = 14, for n >= 3. -
Taras Goy
, Mar 19 2019
a(n) = (2^(-2-n)*((5-sqrt(17))^n*(-7+sqrt(17)) + (5+sqrt(17))^n*(7+sqrt(17)))) / sqrt(17) for n > 0. -
Colin Barker
, Mar 19 2019
a(n) =
A052913
(n)-
A052913
(n-1). -
R. J. Mathar
, Sep 20 2020
MATHEMATICA
Join[{1}, LinearRecurrence[{5, -2}, {3, 14}, 22]] (*
Jean-François Alcover
, Aug 07 2018 *)
PROG
(PARI) Vec((1 - x)^2 / (1 - 5*x + 2*x^2) + O(x^25)) \\
Colin Barker
, Mar 19 2019
CROSSREFS
Cf.
A001906
,
A052530
,
A033453
,
A030017
,
A052913
(partial sums).
Sequence in context:
A026243
A058139
A101476
*
A292744
A151239
A151240
Adjacent sequences:
A060798
A060799
A060800
*
A060802
A060803
A060804
KEYWORD
nonn
,
easy
AUTHOR
Vladeta Jovovic
, Apr 27 2001
STATUS
approved