This sequence appears to be a permutation of the positive integers. -
Leroy Quet, Jan 08 2007
Theorem: This is a permutation of the positive integers.
Proof: (Outline. For details see the link.)
1. Sequence is infinite.
2. For all m, either m is in the sequence or there exists an n_0 such that for n >= n_0, a(n) > m.
3. For all primes p, there is a term divisible by p.
4. For all primes p, there are infinitely many multiples of p in the sequence.
5. Every prime appears in the sequence.
6. For any number m, there are infinitely many multiples of m in the sequence.
7. Every number m appears in the sequence.
(End)
There are several short cycles and at least one apparently infinite orbit:
[1], [2], [3, 4], [5, 6], [7, 10, 8],
[9, 14, 22, 19, 16, 26, 24, 20, 17, 15, 13, 11],
[21, 34, 29, 25],
and the first apparently infinite orbit is, in the forward direction,
[23, 38, 33, 32, 28, 46, 41, 40, 35, 58, 51, 45, 42, 37, 62, 106, ...] (see
A282712), and in the reverse direction
[23, 27, 31, 36, 39, 44, 50, 57, 65, 73, 82, 47, 53, 61, 68, 77, ...] (see
A282713). (End)
Conjecture: The two lines in the graph are (apart from small local deviations) defined by the same equations as the two lines in the graph of
A283312. -
N. J. A. Sloane, Mar 12 2017