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A166916
a(n) = 20*a(n-1) - 64*a(n-2) - 15 for n > 1; a(0) = 357, a(1) = 5525.
10
357, 5525, 87637, 1399125, 22373717, 357930325, 5726688597, 91626231125, 1466016552277, 23456252253525, 375299985724757, 6004799570269525, 96076792319006037, 1537228673882871125, 24595658769241036117
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OFFSET
0,1
COMMENTS
Related to Reverse and Add trajectory of 318 in base 4:
A075153
(6*n+4) = 30*a(n).
lim_{n -> infinity} a(n)/a(n-1) = 16.
LINKS
G. C. Greubel,
Table of n, a(n) for n = 0..500
Index entries for linear recurrences with constant coefficients
, signature (21, -84, 64).
FORMULA
a(n) = (1024*16^n + 48*4^n - 1)/3.
G.f.: (357 - 1972*x + 1600*x^2)/((1-x)*(1-4*x)*(1-16*x)).
a(0)=357, a(1)=5525, a(2)=87637, a(n)=21*a(n-1)-84*a(n-2)+64*a(n-3). -
Harvey P. Dale
, Sep 24 2012
E.g.f.: (1/3)*(1024*exp(16*x) + 48*exp(4*x) - exp(x)). -
G. C. Greubel
, May 28 2016
MATHEMATICA
LinearRecurrence[{21, -84, 64}, {357, 5525, 87637}, 20] (*
Harvey P. Dale
, Sep 24 2012 *)
PROG
(PARI) m=15; v=concat([357, 5525], vector(m-2)); for(n=3, m, v[n]=20*v[n-1]-64*v[n-2]-15); v
CROSSREFS
Cf.
A075153
,
A166912
,
A166913
,
A166914
,
A166915
,
A166917
,
A006105
,
A167031
,
A167032
,
A167033
.
Sequence in context:
A252806
A252027
A241931
*
A166913
A224434
A383114
Adjacent sequences:
A166913
A166914
A166915
*
A166917
A166918
A166919
KEYWORD
nonn
,
easy
AUTHOR
Klaus Brockhaus
, Oct 27 2009
STATUS
approved