The fifth and sixth terms are both cubes, exploiting the simple binomial expansion as (m)(m)^3=(m^3)(3m^3)(3m^3)(m^3) for much of their status. - James G. Merickel, Dec 19 2009
The first base in which the fifth term is 4-palindromic is 209. - James G. Merickel, Dec 18 2009