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A178348
a(n) = Sum_{k=0..n} 1100^k.
1
1, 1101, 1211101, 1332211101, 1465432211101, 1611975432211101, 1773172975432211101, 1950490272975432211101, 2145539300272975432211101, 2360093230300272975432211101, 2596102553330300272975432211101, 2855712808663330300272975432211101
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OFFSET
0,2
LINKS
Colin Barker,
Table of n, a(n) for n = 0..328
Index entries for linear recurrences with constant coefficients
, signature (1101,-1100).
FORMULA
a(n) = 1100*a(n-1) + 1.
Limit_{n -> oo} a(n)/1100^n = 1100/1099.
From
Colin Barker
, Oct 02 2015: (Start)
a(n) = 1101*a(n-1) - 1100*a(n-2) for n>=2.
G.f.: 1/((x-1)*(1100*x-1)). (End)
E.g.f.: exp(x)*(-1 + 1100*exp(1099*x))/1099. -
Elmo R. Oliveira
, Apr 02 2026
EXAMPLE
As overlapping Pascal triangles:
.....1
....1.1.0.1
...1.2.1.1.1.0.1
..1.3.3.2.2.1.1.1.0.1
.1.4.6.5.4.3.2.2.1.1.1.0.1
MATHEMATICA
Table[Sum[1100^k, {k, 0, n}], {n, 0, 11}] (*
Michael De Vlieger
, Oct 02 2015 *)
PROG
(PARI) Vec(1/((x-1)*(1100*x-1)) + O(x^25)) \\
Colin Barker
, Oct 02 2015
(PARI) vector(100, n, n--; sum(k=0, n, 1100^k)) \\
Altug Alkan
, Oct 06 2015
(Magma) [(1/1099)*(1100^n-1): n in [0..20]]; //
Vincenzo Librandi
, Oct 07 2015
CROSSREFS
Cf.
A000931
,
A007318
.
Sequence in context:
A283172
A283253
A178407
*
A359149
A250796
A271431
Adjacent sequences:
A178345
A178346
A178347
*
A178349
A178350
A178351
KEYWORD
nonn
,
easy
,
changed
AUTHOR
Mark Dols
, May 25 2010
EXTENSIONS
Offset corrected by
Joerg Arndt
, Oct 03 2015
STATUS
approved