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A228036
(10^n)-th primitive antiharmonic number.
3
1, 605, 51005, 5837732, 599407380, 60462121402
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OFFSET
0,2
COMMENTS
We conjecture that lim_{n->oo} a(n)/100^n = lim_{n->oo}
A228023
(n)/n^2 = 6. This is supported by the values a(n)/(10^n)^2 = 6.05, 5.10, 5.84, 5.99, 6.05 for n = 1..5, as well as by the values of
A228023
(n)/n^2.
LINKS
Table of n, a(n) for n=0..5.
FORMULA
a(n) =
A228023
(10^n).
CROSSREFS
Cf.
A020487
,
A227771
,
A228023
,
A228024
.
Sequence in context:
A234338
A250969
A265244
*
A274765
A249524
A064250
Adjacent sequences:
A228033
A228034
A228035
*
A228037
A228038
A228039
KEYWORD
nonn
AUTHOR
Jonathan Sondow
and
Charles R Greathouse IV
, Aug 04 2013
EXTENSIONS
a(5) from
Charles R Greathouse IV
, Sep 03 2013
STATUS
approved