E.g.f.: A(x) = 1 + 5*x + 115*x^2/2! + 23075*x^3/3! + 45885991*x^4/4! +...
Illustration of initial terms:
a(1) = (1 + 1) + 3 = 5;
a(2) = (1 + 1)^2 + 2*(2 + 3)*3 + 3^4 = 115;
a(3) = (1 + 1)^3 + 3*(2 + 3)^2*3 + 3*(2^2 + 3^2)*3^4 + 3^9 = 23075;
a(4) = (1 + 1)^4 + 4*(2 + 3)^3*3 + 6*(2^2 + 3^2)^2*3^4 + 4*(2^3 + 3^3)*3^9 + 3^16 = 45885991;
a(5) = (1 + 1)^5 + 5*(2 + 3)^4*3 + 10*(2^2 + 3^2)^3*3^4 + 10*(2^3 + 3^3)^2*3^9 + 5*(2^4 + 3^4)*3^16 + 3^25 = 868409174855; ...
and by the binomial identity:
a(1) = 1 + (1 + 3) = 5;
a(2) = 1 + 2*(1 + 2*3) + (1 + 3^2)^2 = 115;
a(3) = 1 + 3*(1 + 2^2*3) + 3*(1 + 2*3^2)^2 + (1 + 3^3)^3 = 23075;
a(4) = 1 + 4*(1 + 2^3*3) + 6*(1 + 2^2*3^2)^2 + 4*(1 + 2*3^3)^3 + (1 + 3^4)^4 = 45885991;
a(5) = 1 + 5*(1 + 2^4*3) + 10*(1 + 2^3*3^2)^2 + 10*(1 + 2^2*3^3)^3 + 5*(1 + 2*3^4)^4 + (1 + 3^5)^5 = 868409174855; ...