Voozh

A270749

(r,1)-greedy sequence, where r(k) = k/log(k+1).

2, 7, 117, 28231, 934841727, 1391154929853413822, 3358221400639080017571595039208647108, 84149630763494298099512446622134485046922136023978562834130778814722933257

(list; graph; refs; listen; history; text; internal format)

OFFSET

1,1

COMMENTS

Let x > 0, and let r = (r(k)) be a sequence of positive irrational numbers. Let a(1) be the least positive integer m such that r(1)/m < x, and inductively let a(n) be the least positive integer m such that r(1)/a(1) + ... + r(n-1)/a(n-1) + r(n)/m < x. The sequence (a(n)) is the (r,x)-greedy sequence. We are interested in choices of r and x for which the series r(1)/a(1) + ... + r(n)/a(n) + ... converges to x. See A270744 for a guide to related sequences.

LINKS

Table of n, a(n) for n=1..8.

FORMULA

a(n) = ceiling(r(n)/s(n)), where s(n) = 1 - r(1)/a(1) - r(2)/a(2) - ... - r(n-1)/a(n-1).

r(1)/a(1) + ... + r(n)/a(n) + ... = 1.

EXAMPLE

a(1) = ceiling(r(1)) = ceiling(1/log(2)) = ceiling(1.442...) = 2;

a(2) = ceiling(r(2)/(1 - r(1)/2)) = 7;

a(3) = ceiling(r(3)/(1 - r(1)/2 - r(2)/7)) = 117.

The first 3 terms of the series r(1)/a(1) + ... + r(n)/a(n) + ... are 0.721..., 0.981..., 0.99991...

MATHEMATICA

$MaxExtraPrecision = Infinity; z = 16;