Voozh

A306311

Lexicographically earliest sequence starting with a(1) = 1 with no duplicate terms such that the n-th digit of the sequence is a divisor of a(n).

1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 18, 16, 24, 17, 25, 19, 32, 21, 36, 22, 28, 23, 35, 26, 45, 27, 54, 33, 34, 38, 29, 39, 42, 44, 46, 48, 56, 52, 51, 57, 55, 58, 66, 64, 65, 62, 49, 75, 68, 63, 69, 72, 76, 78, 88, 74, 81, 84, 99, 92, 82, 96, 112, 116, 114, 124, 128, 85, 126, 95, 86, 115, 31, 125, 77, 135, 145, 155

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OFFSET

1,2

COMMENTS

This sequence is a derangement of the zeroless numbers; any 0 digit in a(n) would force a division by zero later in the sequence.

LINKS

Jean-Marc Falcoz, Table of n, a(n) for n = 1..20010

EXAMPLE

The sequence starts with 1,2,3,4,5,6,7,8,9,11,12,13,14,15,18,16,24,17,25,19,32,21,...

The first nine terms speak for themselves;

the 10th digit of the sequence is 1 and 1 is a divisor of a(10) = 11;

the 11th digit of the sequence is 1 and 1 is a divisor of a(11) = 12;