If a(n-1) > 10 and the last digit of a(n-1) <= 4, then a(n) <= (10^(A055642(a(n-1))-1)+1)*a(n-1).
For n=6..8, a(n) = 196930692 * A002275(2^(n-3)), and it follows that a(9) <= 196930692 * A002275(64). Conjecture: for all n >= 6, a(n) = 196930692 * A002275(2^(n-3)). Note that 196930692 is a term of A370052 and A370053. - Max Alekseyev, Feb 15 2024