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A392337
Triangle read by rows: T(n,k) = Sum_{j=0..2k} (-1)^j * binomial(2k,j) * (1+k-j)^(2n).
0
1, 1, 2, 1, 14, 24, 1, 62, 480, 720, 1, 254, 5544, 30240, 40320, 1, 1022, 54960, 710640, 3024000, 3628800, 1, 4094, 515064, 13654080, 125072640, 439084800, 479001600, 1, 16382, 4717440, 239999760, 4093689600, 29059430400, 87178291200, 87178291200
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OFFSET
0,3
LINKS
Table of n, a(n) for n=0..35.
Donald E. Knuth,
Johann Faulhaber and Sums of Powers
, arXiv:math/9207222 [math.CA], 1992.
Petro Kolosov,
Mathematica programs
, GitHub, 2026.
Petro Kolosov,
Sums of powers via central finite differences and Newton's formula
, Zenodo, 2026.
FORMULA
Let F(t,n,k) be a 2k-order central finite difference of power t^(2n): F(t,n,k) = Sum_{j=0..2k} (-1)^j * binomial(2k,j) * (t+k-j)^(2n). Then:
T(n,k) = F(1, n, k).
EXAMPLE
Triangle begins:
k= 0 1 2 3 4 5 6
-----------------------------------------------------------------
n=0: 1;
n=1: 1, 2;
n=2: 1, 14, 24;
n=3: 1, 62, 480, 720;
n=4: 1, 254, 5544, 30240, 40320;
n=5: 1, 1022, 54960, 710640, 3024000, 3628800;
n=6: 1, 4094, 515064, 13654080, 125072640, 439084800, 479001600;
...
MATHEMATICA
T[t_, n_, k_] := Sum[(-1)^j * Binomial[2 k, j]* (t + k - j)^(2 n), {j, 0, 2 k}]; Table[T[1, n, k], {n, 0, 10}, {k, 0, n}] // Flatten
CROSSREFS
Cf.
A008957
,
A269945
.
Sequence in context:
A245733
A276851
A080346
*
A216445
A124026
A106204
Adjacent sequences:
A392333
A392334
A392336
*
A392338
A392339
A392340
KEYWORD
nonn
,
tabl
,
easy
,
changed
AUTHOR
Petro Kolosov
, Jan 07 2026
STATUS
approved