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a(n) = Sum_{i=1..floor((n+1)/4)} a(2*i-1) * a(n-2*i+1), with a(1)=2 and a(2)=a(3)=1.
#6 by Alois P. Heinz at Sun Jul 21 18:23:18 EDT 2019
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#5 by Sean A. Irvine at Sun Jul 21 17:18:08 EDT 2019
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#4 by Sean A. Irvine at Sun Jul 21 17:18:02 EDT 2019
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#3 by Russ Cox at Fri Mar 30 18:55:59 EDT 2012
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Fri Mar 30
18:55
OEIS Server: https://oeis.org/edit/global/285
#2 by N. J. A. Sloane at Fri May 16 03:00:00 EDT 2003
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#1 by N. J. A. Sloane at Sat Dec 11 03:00:00 EST 1999
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