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⇱ The On-Line Encyclopedia of Integer Sequences (OEIS)


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Showing entries 1-10 | older changes
Numbers k such that k*floor(2^k/k) + 1 is prime.
#71 by Bruno Berselli at Fri Oct 26 10:32:48 EDT 2018
STATUS
#70 by Bruno Berselli at Fri Oct 26 10:32:45 EDT 2018
COMMENTS
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#69 by Bruno Berselli at Fri Oct 26 10:31:25 EDT 2018
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#68 by Bruno Berselli at Fri Oct 26 10:31:08 EDT 2018
NAME
COMMENTS
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#67 by Michel Marcus at Fri Oct 26 06:40:33 EDT 2018
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#66 by Thomas Ordowski at Thu Oct 11 05:45:56 EDT 2018
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#65 by Thomas Ordowski at Thu Oct 11 05:44:55 EDT 2018
COMMENTS
STATUS
#64 by Michel Marcus at Wed Oct 10 00:54:22 EDT 2018
STATUS
Discussion
Wed Oct 10
01:12
G. C. Greubel: Spent the day waiting on machine to get terms up to n<30000, added them hit enter to realize I was minutes too late. Darn!
01:13
G. C. Greubel: Terms for n<=31000 have been verified.
01:25
Thomas Ordowski: Thank you very much!
04:23
Thomas Ordowski: Conjecture: k = n[2^n/n]+1 is prime iff 3^(k-1) == 1 (mod k).
04:29
Thomas Ordowski: For n > 1.
Thu Oct 11
05:22
Thomas Ordowski: Problem: Are there composite numbers n such that 2^n - (2^(n-1) mod n) is prime?
05:30
Thomas Ordowski: The equivalent form of these primes is 2^(n-1) + n[2^n-1)/n]. Are, for n > 2, they all the Mersenne primes?
05:37
Thomas Ordowski: Correction. Above should be: 2^(n-1) + n[2^(n-1)/n].
#63 by Michel Marcus at Wed Oct 10 00:54:18 EDT 2018
EXTENSIONS
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#62 by Thomas Ordowski at Wed Oct 10 00:51:22 EDT 2018
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Discussion
Wed Oct 10
00:53
Thomas Ordowski: I added them to the data, thanks!