a(n) = (-1)^(n+1) * (3^n+1)/2.
Discussion
Sat Feb 13
04:00
Jon E. Schoenfield: Please disregard my question. I'm badly ignorant of the subject matter.
Discussion
Sat Feb 13
00:07
Jon E. Schoenfield: I may be misunderstanding the notation, but does the period in "f(G) =(-1)^n.Q(G)" mean multiplication? Or something else?
Discussion
Fri Feb 12
22:33
Kevin Ryde: Maybe the balanced ternary could be clearer. Perhaps letter T for -1 to avoid parens.
Discussion
Fri Feb 12
20:23
Omar E. Pol: Minor edits.