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URL: https://willitrunai.com/can-run/baichuan-13b-on-m4-max-64gb


Can Baichuan 13B run on MacBook Pro M4 Max 64GB?

YES — Runs Great

B69Good
Estimated from fit model

Baichuan 13B needs ~29.4 GB VRAM. MacBook Pro M4 Max 64GB has 46.1 GB. With Q5_K_M quantization, expect ~38 tok/s.

Runtime: llama.cppCapacity: RoomyBandwidth: MediumStack: StandardBottleneck: Balanced
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Operating mode

Choose the run profile you care about

Interactive favors responsiveness, while light API and scale-out lean harder on serving readiness. The fit stays the same, but the recommendation lens changes.

Current mode

Balanced

Balanced for general local use. Keeps the ranking neutral across personal and serving workflows.

Capabilities:

Select quantization to explore

Q5_K_M (High quality) — 29.4 GB, 33.0 tok/s, Runs well
29.4 GB required46.1 GB available
64% VRAM used

Fit status

Runs well

Decode

33.0 tok/s

TTFT

5869 ms

Safe context

8K

Memory

29.4 GB / 46.1 GB

Memory breakdown

Weights9.4 GB
KV Cache12.2 GB
Runtime0.9 GB
Headroom6.9 GB

See how fast it feels

See how fast it feelsBaichuan 13B on MacBook Pro M4 Max 64GB
1st promptCold start — includes initialization
>Solve: If a train travels at 60 mph for 2.5 hours, how far does it go?
Let me work through this step by step. Given information: - Speed = 60 mph (miles per hour) - Time = 2.5 hours Formula: Distance = Speed x Time Calculation: Distance = 60 mph x 2.5 h = 150 miles The train travels 150 miles. Double-check: at 60 mph the train covers 60 miles each hour. In half an hour it covers 30 miles. So in 2.5 hours: 60 + 60 + 30 = 150 miles. Confirmed.
2nd promptWarm — model ready, no init overhead
>What if the train stops for 20 minutes halfway?
The stop doesn't change the total distance covered while moving, but it affects total trip time. Breakdown: - First half: 1.25 hours at 60 mph = 75 miles - Stop: 20 minutes (no distance) - Second half: 1.25 hours at 60 mph = 75 miles Total distance: 150 miles (same) Total time: 2.5 h + 0.33 h = 2.83 hours Average speed: 150 / 2.83 = 53 mph The distance stays the same but average speed drops to 53 mph because of the stop.
Estimated: 33.0 tok/s decode · 5.9s TTFT (warm) · 83 tok/s prefill

What limits this setup

This setup is broadly balanced for this model.

Shared-memory contention still exists

The OS, browser, and inference runtime all compete for the same physical memory pool, so real-world headroom is less forgiving than raw capacity suggests.

Best improvement path

Performance by workload

WorkloadGradeFitDecodeTTFTContext
ChatBRuns well33.0 tok/s3201 ms8K
CodingBRuns well37.5 tok/s5165 ms8K
Agentic CodingBTight fit33.0 tok/s8537 ms8K
ReasoningBRuns well33.0 tok/s6936 ms8K
RAGBTight fit33.0 tok/s10671 ms8K

Quantization options

How Baichuan 13B (13B params) fits at each quantization level on MacBook Pro M4 Max 64GB (46.1 GB usable).

QuantBitsVRAMQualityFit
Q2_K
2
5.1 GB
LowB58
Q3_K_S
3
6.4 GB
LowB58
NVFP4
4

Get started

Copy-paste commands to run Baichuan 13B on your machine.

Run

docker run --rm -it ghcr.io/ggerganov/llama.cpp:full \ --hf-repo "baichuan-inc/Baichuan-13B-Chat" \ --hf-file "Baichuan-13B-Chat-Q5_K_M.gguf" \ -c 4096 -ngl 99

Upgrade options

Hardware that runs Baichuan 13B well

Radeon Pro W7900 48GBBudget pick
864 GB/s (+318)
B
Raises estimated decode speed by about 68%.55.6 tok/s decode

Raises estimated decode speed by about 68%.

~$3,999 MSRP

Radeon PRO W7900 DS 48GBBest value
864 GB/s (+318)
B
Raises estimated decode speed by about 68%.55.6 tok/s decode

Raises estimated decode speed by about 68%.

~$3,999 MSRP

Frequently asked questions

See all results for MacBook Pro M4 Max 64GBSee all hardware for Baichuan 13B
7.3 GB
Medium
B58
Q4_K_M
4
7.9 GB
MediumB59
Q5_K_M
5
9.4 GB
HighB59
Q6_K
6
10.7 GB
HighB59
Q8_0
8
13.9 GB
Very HighB60
F16Best for your GPU
16
26.7 GB
MaximumB64

Not always. MacBook Pro M4 Max 64GB can often fit larger models thanks to unified memory, but a discrete GPU with dedicated high-bandwidth VRAM may still decode faster once the model fits. For this combination, the important distinction is capacity versus sustained throughput.