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There are many situations where we use integer values as index in array to see presence or absence, we can use bit manipulations to optimize space in such problems.
Let us consider below problem as an example.
Given two numbers say a and b, mark the multiples of 2 and 5 between a and b using less than O(|b - a|) space and output each of the multiples.
Note : We have to mark the multiples i.e save (key, value) pairs in memory such that each key either have value as 1 or 0 representing as multiple of 2 or 5 or not respectively.
Examples :
Input : 2 10 Output : 2 4 5 6 8 10 Input: 60 95 Output: 60 62 64 65 66 68 70 72 74 75 76 78 80 82 84 85 86 88 90 92 94 95
Approach 1 (Simple):
Hash the indices in an array from a to b and mark each of the indices as 1 or 0.
Space complexity : O(max(a, b))
Approach 2 (Better than simple):
Save memory, by translating a to 0th index and b to (b-a)th index.
Space complexity : O(|b-a|).
Simply hash |b - a| positions of an array as 0 and 1.
Implementation:
MULTIPLES of 2 and 5: 2 4 5 6 8 10
Time Complexity: O(|b - a|)
Auxiliary space: O(|b - a|)
Approach 3 (Using Bit Manipulations):
Here is a space optimized which uses bit manipulation technique that can be applied to problems mapping binary values in arrays.
Size of int variable in 64-bit compiler is 4 bytes. 1 byte is represented by 8 bit positions in memory. So, an integer in memory is represented by 32 bit positions(4 Bytes) these 32 bit positions can be used instead of just one index to hash binary values.
We can Implement the above Approach for 32-bit integers by following these steps
Implementation:
MULTIPLES of 2 and 5: 2 4 5 6 8 10
Time Complexity: O(|b - a|)
Auxiliary space: O(|b - a|)