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C/C++ program to add N distances given in inch-feet system using Structures

Last Updated : 12 Jul, 2025
Given an array arr[] containing N distances of inch-feet system, such that each element of the array represents a distance in the form of {inch, feet}. The task is to add all the N inch-feet distances using structures. Examples:
Input: arr[] = { { 10, 3.7 }, { 10, 5.5 }, { 6, 8.0 } }; Output: Feet Sum: 27 Inch Sum: 5.20 Input: arr[] = { { 1, 1.7 }, { 1, 1.5 }, { 6, 8 } }; Output: Feet Sum: 8 Inch Sum: 11.20
Approach:
  1. Traverse the struct array arr and find the summation of all the inches of the given set of N distances as:
    feet_sum = feet_sum + arr[i].feet;
    inch_sum = inch_sum + arr[i].inch;
    
  2. If the sum of all the inches (say inch_sum) is greater than 12, then convert the inch_sum into feet because
    1 feet = 12 inches
    
    Therefore update inch_sum to inch_sum % 12. Then find the summation of all the feets(say feet_sum) of N distances and add inches_sum/12 to this sum.
  3. Print the feet_sum and inch_sum individually.
Below is the implementation of the above approach:
Output:
Feet Sum: 27
Inch Sum: 5.20
Time Complexity: O(N), where N is the number inch-feet distances.
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