Can C++ reference member be declared without being initialized with declaration?

To many readers, this might sound the same thing, i.e. 
 

class_type *var = NULL;
*var = &some_work;

is same as

class_type *var = &some_work;

But in actual, it is not. When the declaration and initialization are done at the same step, the compiler calls the copy constructor whereas if done in another step, the compiler calls the default constructor.
To understand this, let's consider an example:
Example 1: When initialization is not done at the same step of the declaration 
 

Output: 
 

10

Example 2: When initialization is done with the declaration 
 

Compile Errors: 
 

prog.cpp: In constructor 'A::A(int)':
prog.cpp:8:5: error: uninitialized reference member in 'int&' [-fpermissive]
 A(int w)
 ^
prog.cpp:5:10: note: 'int& A::p' should be initialized
 int& p;
 ^

Note: In this code, as soon as an object is created compiler will allocate memory to p by running the constructor of class A. Now as we know reference variable needs to be initialized at the same step so it will pop up an error message called "reference member is not initialized" . 
As we have seen in code 1, initialization is not done at the same step of the declaration, but still, our code runs. But in general, it is a rule that "reference member should be initialized and declared at the same step."
So the answer to the above question is both yes and no.