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C++ STL offer many utilities to solve basic common life problems. Comparing values are always necessary, but sometimes we need to compare the strings also. Therefore, this article aims at explaining about "lexicographical_compare()" that allows to compare strings. This function is defined in "algorithm" header. It has two implementations. Syntax 1 : lexicographical_compare(iter1 beg1, iter1 end1, iter2 beg2, iter2 end2)
Template: template bool lexicographical_compare(iter1 beg1, iter1 end1, iter2 beg2, iter2 end2) Parameters : beg1 : Input iterator to initial position of first sequence. end1 : Input iterator to final position of first sequence. beg2 : Input iterator to initial position of second sequence. end2 : Input iterator to final position of second sequence. Return value : Returns a boolean true, if range1 is strictly lexicographically smaller than range2 else returns a false.
Time Complexity: O(N)
Space Complexity: O(1)
Output:
geeksforgeeks is lexicographically less than gfg
Syntax 2 : lexicographical_compare(iter1 beg1, iter1 end1, iter2 beg2, iter2 end2, Compare comp)
Template: template bool lexicographical_compare(iter1 beg1, iter1 end1, iter2 beg2, iter2 end2) Parameters : beg1 : Input iterator to initial position of first sequence. end1 : Input iterator to final position of first sequence. beg2 : Input iterator to initial position of second sequence. end2 : Input iterator to final position of second sequence. comp : The comparator function that returns a boolean true/false of the each elements compared. This function accepts two arguments. This can be function pointer or function object and cannot change values. Return value : Returns a boolean true, if range1 is strictly lexicographically smaller than range2 else returns a false.
Time Complexity: O(N)
Space Complexity: O(1)
Output:
geeksforgeeks is not lexicographically less than Gfg geeksforgeeks is lexicographically less than Gfg( case-insensitive )
Possible application : Comparing strings can be generally used in dictionary, where we need to place words in lexicographical order. Example of this can be to find the word which occurs 1st in dictionary among given set of words.
Time Complexity: O(N)
Space Complexity: O(1)
Output:
The smallest string is : abacus