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Consider a binary array consisting of N elements (initially all elements are 0). After that, you are given M commands where each command is of form a b, which means you have to toggle all the elements of the array in range a to b (both inclusive). After the execution of all M commands, you have to find the resultant array.
Examples:
Input : N = 5, M = 3
C1 = 1 3, C2 = 4 5, C3 = 1 4
Output : Resultant array = {0, 0, 0, 0, 1}
Explanation :
Initial array : {0, 0, 0, 0, 0}
After first toggle : {1, 1, 1, 0, 0}
After second toggle : {1, 1, 1, 1, 1}
After third toggle : {0, 0, 0, 0, 1}
Input : N = 5, M = 5
C1 = 1 5, C2 = 1 5, C3 = 1 5,
C4 = 1 5, C5 = 1 5
Output : Resultant array = {1, 1, 1, 1, 1}
Naive Approach: For the given N we should create a bool array of n+1 elements and for each of M commands we have to iterate from a to b and toggle all elements in the range of a to b with help of XOR.
The complexity of this approach is O(n^2).
for (int i = 1; i > a >> b; for (int j = a; j <= b; j++) arr[j] ^= 1;
Efficient Approach: The idea is based on the sample problem discussed in the Prefix Sum Array article. For the given n, we create a bool array of n+2 elements and for each of M commands, we have to just toggle elements a and b+1 with help of XOR. After all commands we will process the array as arr[i] ^= arr[i-1];
The complexity of this approach is O(n).
Implementation:
1 0 1 1 1
Time Complexity: O(n)
Auxiliary Space: O(1)