Find the hypotenuse of a right angled triangle with given two sides

Given the other two sides of a right angled triangle, the task is to find it's hypotenuse.
Examples:

Input: side1 = 3, side2 = 4 
Output: 5.00 
3² + 4² = 5²
Input: side1 = 12, side2 = 15 
Output: 19.21 

Approach:Pythagoras theorem states that the square of hypotenuse of a right angled triangle is equal to the sum of squares of the other two sides.
Below is the implementation of the above approach:

5.00

Time Complexity: O(log(2*(s²)) where s is the side of the rectangle. because time complexity of inbuilt sqrt function is O(log(n))

Auxiliary Space: O(1)