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Forming smallest array with given constraints

Last Updated : 17 Aug, 2022

Given three integers x, y and z (can be negative). The task is to find the length of the smallest array that can be made such that absolute difference between adjacent elements is less than or equal to 1, the first element of the array is x, having one integer y and last element z.

Examples: 

Input : x = 5, y = 7, z = 11 
Output :
The smallest starts with 5, having 7, ends 
with 11 and having absolute difference 1 
is { 5, 6, 7, 8, 9, 10, 11 }.

Input : x = 3, y = 1, z = 2 
Output :
The array would become { 3, 2, 1, 2 }  

The idea is to consider the number line since the difference between adjacent elements is 1 so to move from X to Y all numbers between x and y have to be covered and to end the array with integer z, so move from element y to element z. 

So, the length of the smallest array that can be formed will be the number of points that will be covered from x to z i.e.  

1 + abs(x - y) + abs(y - z) (1 is added to count point x).

Implementation:


Output
4

Complexity Analysis:

  • Time Complexity: O(1)
  • Auxiliary Space: O(1)
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