VOOZH about

URL: https://www.javacodegeeks.com/2014/02/java-8-sorting-values-in-collections.html

⇱ Java 8: Sorting values in collections


Having realised that Java 8 is due for its GA release within the next few weeks I thought it was about time I had a look at it and over the last week have been reading Venkat Subramaniam’s book.

I’m up to chapter 3 which covers sorting a collection of people. The Person class is defined roughly like so:
 
 
 
 
 

static class Person {
 private String name;
 private int age;

 Person(String name, int age) {
 this.name = name;
 this.age = age;
 }

 @Override
 public String toString() {
 return String.format("Person{name='%s', age=%d}", name, age);
 }
}

In the first example we take a list of people and then sort them in ascending age order:

List<Person> people = Arrays.asList(new Person("Paul", 24), new Person("Mark", 30), new Person("Will", 28));
people.stream().sorted((p1, p2) -> p1.age - p2.age).forEach(System.out::println);
Person{name='Paul', age=24}
Person{name='Will', age=28}
Person{name='Mark', age=30}

If we were to write a function to do the same thing in Java 7 it’d look like this:

Collections.sort(people, new Comparator<Person>() {
 @Override
 public int compare(Person o1, Person o2) {
 return o1.age - o2.age;
 }
});

for (Person person : people) {
 System.out.println(person);
}

Java 8 has reduced the amount of code we have to write although it’s still more complicated than what we could do in Ruby:

> people = [ {:name => "Paul", :age => 24}, {:name => "Mark", :age => 30}, {:name => "Will", :age => 28}]
> people.sort_by { |p| p[:age] }
=> [{:name=>"Paul", :age=>24}, {:name=>"Will", :age=>28}, {:name=>"Mark", :age=>30}]

A few pages later Venkat shows how you can get close to this by using the Comparator#comparing function:

Function<Person, Integer> byAge = p -> p.age ;
people.stream().sorted(comparing(byAge)).forEach(System.out::println);

I thought I could make this simpler by inlining the ‘byAge’ lambda like this:

people.stream().sorted(comparing(p -> p.age)).forEach(System.out::println);

This seems to compile and run correctly although IntelliJ 13.0 suggests there is a ‘cyclic inference‘ problem. IntelliJ is happy if we explicitly cast the lambda like this:

people.stream().sorted(comparing((Function<Person, Integer>) p -> p.age)).forEach(System.out::println);

IntelliJ also seems happy if we explicitly type ‘p’ in the lambda, so I think I’ll go with that for the moment:

people.stream().sorted(comparing((Person p) -> p.age)).forEach(System.out::println);
Reference: Java 8: Sorting values in collections from our JCG partner Mark Needham at the Mark Needham Blog blog.
Do you want to know how to develop your skillset to become a Java Rockstar?
Subscribe to our newsletter to start Rocking right now!
To get you started we give you our best selling eBooks for FREE!
1. JPA Mini Book
2. JVM Troubleshooting Guide
3. JUnit Tutorial for Unit Testing
4. Java Annotations Tutorial
5. Java Interview Questions
6. Spring Interview Questions
7. Android UI Design
and many more ....
I agree to the Terms and Privacy Policy

Thank you!

We will contact you soon.

Tags
Java 8
👁 Photo of Mark Needham
Mark Needham
February 27th, 2014Last Updated: February 27th, 2014
1 102 1 minute read
Subscribe

This site uses Akismet to reduce spam. Learn how your comment data is processed.

1 Comment
Oldest
Newest Most Voted
Why
12 years ago

Compared to Scala.

case class Person(name: String, age: Int)
val people = List(Person(“Paul”, 24), Person(“Mark”, 30), Person(“Will”, 28))
people.sortBy(_.age).foreach(prinln)

Java syntax is way to verbose and repetitive.

0
Reply
Back to top button
Close
wpDiscuz