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URL: https://en.wikipedia.org/wiki/Epicycloid

⇱ Epicycloid - Wikipedia


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Plane curve traced by a point on a circle rolled around another circle
πŸ‘ Image
The red curve is an epicycloid traced as the small circle (radius r = 1) rolls around the outside of the large circle (radius R = 3).

In geometry, an epicycloid (also called hypercycloid)[1] is a plane curve produced by tracing the path of a chosen point on the circumference of a circleβ€”called an epicycleβ€”which rolls without slipping around a fixed circle. It is a particular kind of roulette.

An epicycloid with a minor radius (R2) of 0 is a circle. This is a degenerate form.

Equations

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If the rolling circle has radius πŸ‘ {\displaystyle r}
, and the fixed circle has radius πŸ‘ {\displaystyle R=kr}
, then the parametric equations for the curve can be given by either:

πŸ‘ {\displaystyle {\begin{aligned}&x(\theta )=(R+r)\cos \theta \ -r\cos \left({\frac {R+r}{r}}\theta \right)\\&y(\theta )=(R+r)\sin \theta \ -r\sin \left({\frac {R+r}{r}}\theta \right)\end{aligned}}}

or:

πŸ‘ {\displaystyle {\begin{aligned}&x(\theta )=r(k+1)\cos \theta -r\cos \left((k+1)\theta \right)\\&y(\theta )=r(k+1)\sin \theta -r\sin \left((k+1)\theta \right).\end{aligned}}}

This can be written in a more concise form using complex numbers as[2]

πŸ‘ {\displaystyle z(\theta )=r\left((k+1)e^{i\theta }-e^{i(k+1)\theta }\right)}

where

Area and arc length

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Assuming the initial point lies on the larger circle, when πŸ‘ {\displaystyle k}
is a positive integer, the area πŸ‘ {\displaystyle A}
and arc length πŸ‘ {\displaystyle s}
of this epicycloid are

πŸ‘ {\displaystyle A=(k+1)(k+2)\pi r^{2},}
πŸ‘ {\displaystyle s=8(k+1)r.}

It means that the epicycloid is πŸ‘ {\displaystyle {\frac {(k+1)(k+2)}{k^{2}}}}
larger in area than the original stationary circle.

If πŸ‘ {\displaystyle k}
is a positive integer, then the curve is closed, and has k cusps (i.e., sharp corners).

If πŸ‘ {\displaystyle k}
is a rational number, say πŸ‘ {\displaystyle k=p/q}
expressed as irreducible fraction, then the curve has πŸ‘ {\displaystyle p}
cusps.

To close the curve and
complete the 1st repeating pattern :
ΞΈ = 0 to q rotations
Ξ± = 0 to p rotations
total rotations of outer rolling circle = p + q rotations

Count the animation rotations to see p and q

If πŸ‘ {\displaystyle k}
is an irrational number, then the curve never closes, and forms a dense subset of the space between the larger circle and a circle of radius πŸ‘ {\displaystyle R+2r}
.

The distance πŸ‘ {\displaystyle {\overline {OP}}}
from the origin to the point πŸ‘ {\displaystyle p}
on the small circle varies up and down as

πŸ‘ {\displaystyle R\leq {\overline {OP}}\leq R+2r}

where

The epicycloid is a special kind of epitrochoid.

An epicycle with one cusp is a cardioid, two cusps is a nephroid.

An epicycloid and its evolute are similar.[3]

Proof

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πŸ‘ Image
sketch for proof

Assuming that the position of πŸ‘ {\displaystyle p}
is what has to be solved, πŸ‘ {\displaystyle \alpha }
is the angle from the tangential point to the moving point πŸ‘ {\displaystyle p}
, and πŸ‘ {\displaystyle \theta }
is the angle from the starting point to the tangential point.

Since there is no sliding between the two cycles, then

πŸ‘ {\displaystyle \ell _{R}=\ell _{r}}

By the definition of angle (which is the rate arc over radius), then

πŸ‘ {\displaystyle \ell _{R}=\theta R}

and

πŸ‘ {\displaystyle \ell _{r}=\alpha r}
.

From these two conditions, the following identity is obtained

πŸ‘ {\displaystyle \theta R=\alpha r}
.

By calculating, the relation between πŸ‘ {\displaystyle \alpha }
and πŸ‘ {\displaystyle \theta }
is obtained, which is

πŸ‘ {\displaystyle \alpha ={\frac {R}{r}}\theta }
.

From the figure, the position of the point πŸ‘ {\displaystyle p}
on the small circle is clearly visible.

πŸ‘ {\displaystyle x=\left(R+r\right)\cos \theta -r\cos \left(\theta +\alpha \right)=\left(R+r\right)\cos \theta -r\cos \left({\frac {R+r}{r}}\theta \right)}
πŸ‘ {\displaystyle y=\left(R+r\right)\sin \theta -r\sin \left(\theta +\alpha \right)=\left(R+r\right)\sin \theta -r\sin \left({\frac {R+r}{r}}\theta \right)}

See also

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πŸ‘ Image
Animated gif with turtle in MSWLogo (Cardioid)[4]

References

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External links

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