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URL: https://oeis.org/A039300

⇱ A039300 - OEIS

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A039300
Number of distinct quadratic residues mod 3^n.
8
1, 2, 4, 11, 31, 92, 274, 821, 2461, 7382, 22144, 66431, 199291, 597872, 1793614, 5380841, 16142521, 48427562, 145282684, 435848051, 1307544151, 3922632452, 11767897354, 35303692061, 105911076181, 317733228542, 953199685624
OFFSET
0,2
COMMENTS
Number of distinct n-digit suffixes of base 3 squares.
In general, for any odd prime p, the number s of quadratic residues mod p^n is given by s = (p^(n+1) + p + 2)/(2p + 2) for even n and s = (p^(n+1) + 2*p + 1)/(2p + 2) for odd n, see A000224. - Lekraj Beedassy, Jan 07 2005
REFERENCES
J. V. Uspensky and M. A. Heaslet, Elementary Number Theory, McGraw-Hill, NY, 1939, p. 324.
LINKS
W. D. Stangl, Counting Squares in Z_n, Mathematics Magazine, pp. 285-289, Vol. 69 No. 4 (October 1996).
FORMULA
a(n) = floor(3*(3^n + 3)/8).
a(n) = A033113(n) + 1.
a(n) = (3^(n+1) + 6 + (-1)^(n+1))/8. - Lekraj Beedassy, Jan 07 2005
G.f.: (1 - x - 3*x^2)/((1 - x)*(1 + x)*(1 - 3*x)). - Michael Somos, Mar 27 2005
a(n) = 2*a(n-1) + 3*a(n-2) - 3 with n > 1, a(0) = 1, a(1) = 1. - Zerinvary Lajos, Dec 14 2008
a(n) = 3*a(n-1) + a(n-2) - 3*a(n-3). Vincenzo Librandi, Apr 21 2012
a(n) = A000224(3^n). - R. J. Mathar, Sep 28 2017
E.g.f.: (1/8)*exp(-x)*(-1+6*exp(2*x)+3*exp(4*x)). - Stefano Spezia, Sep 04 2018
MAPLE
A039300 := proc(n)
floor((3^n+3)*3/8) ;
end proc:
seq(A039300(n), n=0..30) ; # R. J. Mathar, Sep 28 2017
MATHEMATICA
CoefficientList[Series[(1-x-3x^2)/((1-x)(1+x)(1-3x)), {x, 0, 30}], x] (* Vincenzo Librandi, Apr 21 2012 *)
Table[Floor((3^n+3)*3/8), {n, 0, 30}] (* Bruno Berselli, Apr 21 2012 *)
CoefficientList[Series[1/8 E^-x (-1 + 6 E^(2 x) + 3 E^(4 x)), {x, 0, 30}], x]*Table[k!, {k, 0, 30}] (* Stefano Spezia, Sep 04 2018 *)
PROG
(PARI) {a(n) = if(n<0, 0, 3^n*3\8 + 1)}; /* Michael Somos, Mar 27 2005 */
(PARI) {a(n) = if(n<1, n==0, 3*a(n-1) - 2 + n%2)}; /* Michael Somos, Mar 27 2005 */
(Magma) [(3^(n+1) + 6 + (-1)^(n+1))/8: n in [0..30]]; // Vincenzo Librandi, Apr 21 2012
(SageMath) [(3^(n+1) +6 -(-1)^n)/8 for n in (0..30)] # G. C. Greubel, Jul 14 2019
(GAP) List([0..30], n-> (3^(n+1) +6 -(-1)^n)/8); # G. C. Greubel, Jul 14 2019
CROSSREFS
KEYWORD
nonn,easy
STATUS
approved