(PARI) a(n)=(n+1)*prod(i=0, n, (n+i)!)/prod(i=1, n+1, i!)
(PARI) a(n) = prod(i=1, n, prod(j=1, n, i+j)); \\
Michel Marcus, Feb 27 2019
(Python)
from math import prod, factorial
def
A079478(n): return prod(i+j for i in range(1, n) for j in range(i+1, n+1))**2*factorial(n)<<n #
Chai Wah Wu, Nov 26 2023