Triangle T(n, k) read by rows; given by [1, 0, 1, 0, 1, 0, 1, 0, 1, 0, ...] DELTA [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ...] where DELTA is Deléham's operator defined in
A084938.
Sum_{k=0..n} T(n, k)*x^k*(1-x)^(n-k) =
A000108(n),
A001003(n),
A007564(n),
A059231(n),
A078009(n),
A078018(n),
A081178(n),
A082147(n),
A082181(n),
A082148(n),
A082173(n) for x = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11. -
Philippe Deléham, Aug 18 2005
Sum_{k=0..n} T(n,k)*x^k = (-1)^n*
A107841(n),
A080243(n),
A000007(n),
A000012(n),
A006318(n),
A103210(n),
A103211(n),
A133305(n),
A133306(n),
A133307(n),
A133308(n),
A133309(n) for x = -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8 respectively. -
Philippe Deléham, Oct 18 2007
O.g.f. (with initial 1 excluded) is the series reversion with respect to x of (1-t*x)*x/(1+x). Cf.
A062991 and
A089434. -
Peter Bala, Jul 31 2012
G.f.: 1 + (1 - x - T(0))/y, where T(k) = 1 - x*(1+y)/( 1 - x*y/T(k+1) ); (continued fraction). -
Sergei N. Gladkovskii, Nov 03 2013
O.g.f. A(x,t) = ( 1 - x - sqrt((1 - x)^2 - 4*x*t) )/(2*x*t) = 1 + (1 + t)*x + (1 + 3*t + 2*t^2)*x^2 + ....
1 + x*(dA(x,t)/dx)/A(x,t) = 1 + (1 + t)*x + (1 + 4*t + 3*t^2)*x^2 + ... is the o.g.f. for
A123160.
For n >= 1, the n-th row polynomial equals (1 + t)/(n+1)*Jacobi_P(n-1,1,1,2*t+1). Removing a factor of 1 + t from the row polynomials gives the row polynomials of
A033282. (End)
The o.g.f. G(x,t) = {1 - (2t+1) x - sqrt[1 - (2t+1) 2x + x^2]}/2x = (t + t^2) x + (t + 3t^2 + 2t^3) x^2 + (t + 6t^2 + 10t^3 + 5t^3) x^3 + ... generating shifted rows of this entry, excluding the first, was given in my 2008 formulas for
A033282 with an o.g.f. f1(x,t) = G(x,t)/(1+t) for
A033282. Simple transformations presented there of f1(x,t) are related to
A060693 and
A001263, the Narayana numbers. See also
A086810.
The inverse of G(x,t) is essentially given in
A033282 by x1, the inverse of f1(x,t): Ginv(x,t) = x [1/(t+x) - 1/(1+t+x)] = [((1+t) - t) / (t(1+t))] x - [((1+t)^2 - t^2) / (t(1+t))^2] x^2 + [((1+t)^3 - t^3) / (t(1+t))^3] x^3 - ... . The coefficients in t of Ginv(xt,t) are the o.g.f.s of the diagonals of the Pascal triangle
A007318 with signed rows and an extra initial column of ones. The numerators give the row o.g.f.s of signed
A074909.
T(n, k) = [x^k] hypergeom([-n, 1 + n], [2], -x). -
Peter Luschny, Apr 26 2022