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A104555
Expansion of x*(1 - x)/(1 - x + x^2)^3.
2
0, 1, 2, 0, -5, -7, 0, 12, 15, 0, -22, -26, 0, 35, 40, 0, -51, -57, 0, 70, 77, 0, -92, -100, 0, 117, 126, 0, -145, -155, 0, 176, 187, 0, -210, -222, 0, 247, 260, 0, -287, -301, 0, 330, 345, 0, -376, -392, 0, 425, 442, 0, -477, -495
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OFFSET
0,3
COMMENTS
Image of C(n+1,2) under the Riordan array (1, x*(1-x)).
LINKS
G. C. Greubel,
Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients
, signature (3,-6,7,-6,3,-1).
FORMULA
a(n) = 3*a(n-1) - 6*a(n-2) + 7*a(n-3) - 6*a(n-4) + 3*a(n-5) - a(n-6).
a(n) = Sum_{k=0..n} binomial(k, n-k)(-1)^(n-k)*k(k+1)/2.
a(n) = Sum_{k=0..floor(n/2)} binomial(n-k, k)(-1)^k*(n-k)(n-k+1)/2.
a(3*n) = 0, a(3*n-2) = n*(3*n - 1)/2, a(3*n-1) = n*(3*n + 1)/2. -
Ralf Stephan
, May 20 2007
a(n) = ((Sum_{k=1..n+1} k^5) mod (Sum_{k=1..n+1} k^3))/((n+1)*(n+2))*(-1)^floor((n mod 6)/4). -
Gary Detlefs
, Oct 31 2011
MAPLE
S:=(j, n)->sum(k^j, k=1..n):seq((S(5, n+1)mod S(3, n+1))/((n+1)*(n+2))*(-1)^floor((n mod 6)/4), n=1..40); #
Gary Detlefs
, Oct 31 2011
MATHEMATICA
CoefficientList[Series[x*(1-x)/(1-x+x^2)^3, {x, 0, 60}], x] (*
Harvey P. Dale
, Apr 13 2011 *)
PROG
(Magma) R<x>:=PowerSeriesRing(Integers(), 60); [0] cat Coefficients(R!( x*(1-x)/(1-x+x^2)^3 )); //
G. C. Greubel
, Jan 01 2023
(SageMath)
def
A104555
_list(prec):
P.<x> = PowerSeriesRing(ZZ, prec)
return P( x*(1-x)/(1-x+x^2)^3 ).list()
A104555
_list(60) #
G. C. Greubel
, Jan 01 2023
CROSSREFS
Cf.
A076118
,
A095130
.
Sequence in context:
A320372
A097709
A197877
*
A140571
A078049
A021490
Adjacent sequences:
A104552
A104553
A104554
*
A104556
A104557
A104558
KEYWORD
easy
,
sign
,
changed
AUTHOR
Paul Barry
, Mar 14 2005
STATUS
approved