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A129362
a(n) = Sum_{k=floor((n+1)/2)..n} J(k+1), J(k) =
A001045
(k).
3
1, 1, 4, 8, 19, 37, 80, 160, 331, 661, 1344, 2688, 5419, 10837, 21760, 43520, 87211, 174421, 349184, 698368, 1397419, 2794837, 5591040, 11182080, 22366891, 44733781, 89473024, 178946048, 357903019, 715806037
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OFFSET
0,3
LINKS
Harvey P. Dale,
Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients
, signature (1,3,-1,0,-2,-4).
FORMULA
G.f.: (1+2*x^3)/((1-x-2*x^2)*(1-x^2-2*x^4)).
a(n) = a(n-1) + 3*a(n-2) - a(n-3) - 2*a(n-5) - 4*a(n-6).
a(n) = Sum_{k=0..n} ( J(k+1) - J((k+1)/2)*(1-(-1)^k)/2 ).
a(n) = Sum_{j=0..floor(n/2)}
A001045
(n-j+1). -
G. C. Greubel
, Jan 31 2024
MATHEMATICA
LinearRecurrence[{1, 3, -1, 0, -2, -4}, {1, 1, 4, 8, 19, 37}, 30] (*
Harvey P. Dale
, Oct 22 2011 *)
PROG
(Magma)
A001045
:= func< n | (2^n - (-1)^n)/3 >;
[(&+[
A001045
(n-j+1): j in [0..Floor(n/2)]]): n in [0..30]]; //
G. C. Greubel
, Jan 31 2024
(SageMath)
def
A001045
(n): return (2^n - (-1)^n)/3
def
A129362
(n): return sum(
A001045
(n-j+1) for j in range(1+(n//2)))
[
A129362
(n) for n in range(31)] #
G. C. Greubel
, Jan 31 2024
CROSSREFS
Cf.
A001045
,
A129361
.
Sequence in context:
A049933
A301746
A163318
*
A301981
A083579
A335714
Adjacent sequences:
A129359
A129360
A129361
*
A129363
A129364
A129365
KEYWORD
nonn
,
easy
AUTHOR
Paul Barry
, Apr 11 2007
STATUS
approved