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A134836
Antidiagonals of the array:
A007318
*
A002260
(transposed).
2
1, 1, 1, 1, 3, 1, 1, 5, 3, 1, 1, 7, 8, 3, 1, 1, 9, 16, 8, 3, 1, 1, 11, 27, 20, 8, 3, 1, 1, 13, 41, 43, 20, 8, 3, 1, 1, 15, 58, 81, 48, 20, 8, 3, 1, 1, 17, 78, 138, 106, 48, 20, 8, 3, 1, 1, 19, 101, 218, 213, 112, 48, 20, 8, 3, 1
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OFFSET
1,5
COMMENTS
Antidiagonals tend to
A001792
starting from the right: (1, 3, 8, 20, 48, 112, ...).
LINKS
Table of n, a(n) for n=1..66.
FORMULA
Antidiagonals of the array:
A007318
*
A002260
(transform), where
A002260
= (1; 1,2; 1,2,3; ...).
EXAMPLE
First few rows of the array:
1, 1, 1, 1, 1, 1, ...;
1, 3, 3, 3, 3, 3, ...;
1, 5, 8, 8, 8, 8, ...;
1, 7, 16, 20, 20, 20, ...;
1, 9, 27, 43, 48, 48, ...;
1, 11, 41, 81, 106, 112, ...;
...
First few rows of the triangle:
1;
1, 1;
1, 3, 1;
1, 5, 3, 1;
1, 7, 8, 3, 1;
1, 9, 16, 8, 3, 1;
1, 11, 27, 20, 8, 3, 1;
1, 13, 41, 43, 20, 8, 3, 1;
...
MAPLE
A002260
:= proc(n, k)
if n <= k then
n+1;
else
0 ;
end if;
end proc:
A007318
:= proc(n, k)
if k <= n then
binomial(n, k) ;
else
0
end if;
end proc:
A134836
:= proc(n, k)
add(
A007318
(n, i)*
A002260
(i, k), i=0..k) ;
end proc:
seq(seq(
A134836
(d-k, k), k=0..d), d=0..12) ; #
R. J. Mathar
, Aug 17 2022
CROSSREFS
Cf.
A002260
,
A001792
,
A116445
(array transposed),
A001629
(antidiagonal sums).
Sequence in context:
A152720
A131247
A114278
*
A180955
A349182
A191751
Adjacent sequences:
A134833
A134834
A134835
*
A134837
A134838
A134839
KEYWORD
nonn
,
tabl
,
easy
AUTHOR
Gary W. Adamson
, Nov 12 2007
EXTENSIONS
One term corrected by
R. J. Mathar
, Aug 17 2022
STATUS
approved