a(n) = ((8*n)!/(24)^(2*n))*Sum_{j=0..2*n} ( b(2*n, j)*b(4*n, j)*(-6)^j )/( j! * b(2*j, j)*b(8*n, 2*j) ), where b(x,y) = binomial(x,y).
a(n) = ((8*n)!/(24)^(2*n))*Hypergeometric1F1([-2*n], [1/2-4*n], -3/2). (End)
a(n) ~ sqrt(Pi) * 2^(18*n + 2) * n^(8*n + 1/2) / (3^(2*n) * exp(8*n + 3/4)). -
Vaclav Kotesovec, Oct 21 2023