The permutation satisfies
A008578(a(n)) = a(
A008578(n)) for all n, and is self-inverse.
The sequence of fixed points begins as 0, 1, 6, 11, 29, 36, 66, 95, 107, 121, 149, 174, 216, 313, 319, 396, 427, ... and is itself multiplicative in a sense that if a and b are fixed points, then also a*b is a fixed point.
The records are 0, 1, 3, 9, 19, 61, 281, 361, 843, 1159, 1811, 3721, 5339, 5433, 17141, 78961, 110471, 236883, 325679, ...
and they occur at positions 0, 1, 2, 4, 5, 7, 13, 25, 26, 35, 37, 49, 65, 74, 91, 169, 259, 338, 455, ...
(Note how the permutations map squares to squares, and in general keep the prime signature the same.)
Composition with similarly constructed
A235199 gives the permutations
A234743 &
A234744 with more open cycle-structure.
The result of applying a permutation of the prime numbers to the prime factors of n. -
Peter Munn, Dec 15 2019