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A284931

Positions of 1 in A284929; complement of A284930.

2, 3, 5, 6, 7, 9, 10, 12, 13, 15, 16, 17, 19, 20, 21, 23, 24, 26, 27, 29, 30, 31, 33, 34, 36, 37, 39, 40, 41, 43, 44, 46, 47, 49, 50, 51, 53, 54, 55, 57, 58, 60, 61, 63, 64, 65, 67, 68, 69, 71, 72, 74, 75, 77, 78, 79, 81, 82, 84, 85, 87, 88, 89, 91, 92, 94

(list; graph; refs; listen; history; text; internal format)

OFFSET

1,1

COMMENTS

Conjecture: -1 < n*sqrt(2) - a(n) < 1, for n >= 1.

LINKS

Clark Kimberling, Table of n, a(n) for n = 1..10000

EXAMPLE

As a word, A284929 = 011011..., in which 0 is in positions 2,3,5,6,7,9,...

MATHEMATICA

s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0, 1, 1}}] &, {0}, 6] (* A284929 *)

Flatten[Position[s, 0]] (* A284930 *)