Voozh

A294550

Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2), where a(0) = 1, a(1) = 2, b(0) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.

1, 2, 10, 21, 42, 76, 133, 226, 379, 628, 1032, 1687, 2748, 4466, 7247, 11748, 19032, 30819, 49893, 80757, 130697, 211503, 342251, 553807, 896113, 1449977, 2346149, 3796187, 6142399, 9938651, 16081117, 26019837, 42101025, 68120935, 110222035, 178343047

(list; graph; refs; listen; history; text; internal format)

OFFSET

0,2

COMMENTS

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A294532 for a guide to related sequences. Conjecture: a(n)/a(n-1) -> (1 + sqrt(5))/2 = golden ratio (A001622).

LINKS

Table of n, a(n) for n=0..35.

Clark Kimberling, Complementary equations, J. Int. Seq. 19 (2007), 1-13.

EXAMPLE

a(0) = 1, a(1) = 2, b(0) = 3, so that

b(1) = 4 (least "new number");

a(2) = a(1) + a(0) + b(1) + b(0) = 10.

Complement: (b(n)) = (3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, ...).

MATHEMATICA

mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;

a[0] = 1; a[1] = 3; b[0] = 2;

a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n - 1] + b[n - 2];