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A247912

Numbers k such that A247911(k+1) = A247911(k).

2, 4, 7, 9, 12, 15, 17, 20, 22, 25, 27, 30, 32, 35, 37, 40, 42, 45, 47, 50, 52, 55, 57, 60, 62, 64, 67, 69, 72, 74, 77, 79, 81, 84, 86, 89, 91, 93, 96, 98, 101, 103, 105, 108, 110, 113, 115, 117, 120, 122, 125, 127, 129, 132, 134, 137, 139, 141, 144, 146

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OFFSET

1,1

COMMENTS

Complement of A247913.

LINKS

Clark Kimberling, Table of n, a(n) for n = 1..500

EXAMPLE

A247911(n+1) - A247911(n) = (1,0,1,0,1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,...), and a(n) is the position of the n-th 0.

MATHEMATICA

$RecursionLimit = 1000; $MaxExtraPrecision = 1000;

z = 300; u[1] = 0; u[2] = 1; u[n_] := u[n] = u[n - 1] + u[n - 2]/(n - 2);