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A man is assigned a task and doubles the amount of work he does each day. If he completes the entire task in 18 days, how many days does it take him to complete 25% of the task?
Solution:
Let the man do x units of work on Day 1. Since the work doubles each day, the amount of work done on Day 2 is 2x, Day 3 is 4x and so on.
So, the total work done by the end of Day 18 is:
This is a geometric series with a first term and a common ratio . The sum of the first 18 terms is:
We are asked to find the day when the man completes of the total work, i.e.
Let the cumulative work done by the end of daybe:
Now, equating this to
Cancel from both sides:
Solving for :
Since,
Therefore, the man completes 25% of the task by the end of Day 16.
Simple Method:
When 100% of the work is completed in 18 days, and the work doubles every day.
50% of the work would be completed on day 17.
Therefore, 25% of the work would have been completed in 16 days.