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13 purple, 15 yellow, and 17 maroon chameleons are found on an island. When two different-coloured chameleons come together, they both turn into the third colour.
Do all chameleons eventually have the same hue after a certain number of pairwise meetings?
Solution:
• We are given 13 purple, 15 yellow, and 17 maroon chameleons. When two chameleons of different colors meet, both change into the third color.
• Consider the quantity (Yellow − Purple). Initially:
Yellow − Purple = 15 − 13 = 2.
• After any meeting, this quantity either remains unchanged or changes by a multiple of 3. Hence, throughout the process:
Yellow − Purple = 2 + 3k (for some integer k),
which means it is never divisible by 3.
• Now consider the final situation where all chameleons become the same color:
If all are purple: Yellow − Purple = 0 − 45 = −45
If all are yellow: Yellow − Purple = 45
If all are maroon: Yellow − Purple = 0In all cases, the value is divisible by 3.
• This creates a contradiction because the value (Yellow − Purple), which is never divisible by 3 during the process, must become divisible by 3 in the final state.
Therefore, it is not possible for all chameleons to eventually have the same color.