C Program to Add N Distances Given in inch-feet System using Structures

Given an array arr[] containing N distances of inch-feet system, such that each element of the array represents a distance in the form of {inch, feet}. The task is to add all the N inch-feet distances using structures.

Examples:

Input: arr[] = { { 10, 3.7 }, { 10, 5.5 }, { 6, 8.0 } }; 
Output: Feet Sum: 27 Inch Sum: 5.20
 
Input: arr[] = { { 1, 1.7 }, { 1, 1.5 }, { 6, 8 } }; 
Output: Feet Sum: 8 Inch Sum: 11.20

Approach

1. Traverse the struct array arr and find the summation of all the inches of the given set of N distances as:

feet_sum = feet_sum + arr[i].feet;
inch_sum = inch_sum + arr[i].inch;

2. If the sum of all the inches (say inch_sum) is greater than 12, then convert the inch_sum into feet because

1 feet = 12 inches

3. Therefore update inch_sum to inch_sum % 12. Then find the summation of all the feet (say feet_sum) of N distances and add inches_sum/12 to this sum.

4. Print the feet_sum and inch_sum individually.

feet_sum = feet_sum + arr[i].feet;
inch_sum = inch_sum + arr[i].inch;

Program to add two distances in the inch-feet System

Below is the implementation of the above approach: 

Feet Sum: 27
Inch Sum: 5.20

The complexity of the above method

Time Complexity: O(N), where N is the number of inch-feet distances.