Output of C programs | Set 31 (Pointers)

Prerequisite: Pointers in C/C++ 

1. Question 1 What will be the output? 

1. output

 2

1. Description: It is possible to assign an array to a pointer. so, when ptr = a; is executed the address of element a[0] is assigned to ptr and *ptr gives the value of element a[0]. When *(ptr + n) is executed the value at the nth location in the array is accessed.
2. Question 2 What will be the output? 

1. Output:

 15

1. Description: ptr = &a; copies the address of a in ptr making *ptr = a and the statement *ptr = *ptr * 3; can be written as a = a * 3; making a as 15.
2. Question 2 What will be the output? 

1. Output:

222
 

1. Description: According to BODMAS rule multiplication is given higher priority. In the expression i * *j * i + *j;, i * *j *i will be evaluated first and gives result 216 and then adding *j i.e., i = 6 the output becomes 222.
2. Question 4 What will be the output? 

1. Output:

x=21 y=504 z=504

1. Description: In the beginning, the address of x is assigned to y and then y to z, it makes y and z similar. when the pointer variables are incremented their value is added with the size of the variable, in this case, y and z are incremented by 4.
2. Question 5 What will be the output? 

1. Output:

x=10 y=10 z=10

1. Description: *y is a pointer variable whereas **z is a pointer to a pointer variable. *y gives the value at the address it holds and **z searches twice i.e., it first takes the value at the address it holds and then gives the value at that address.

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