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Predict the output of the below program
36
Explanation: Preprocessor replaces square(6) by 6*6 and the expression becomes x = 36/6*6 and value of x is calculated as 36. If we want correct behavior from macro square(x), we should declare it as #define square(x) ((x)*(x)) /* Note that the expression (x*x) will also fail for square(6-2) */