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Probability is a numerical representation of the chance of occurrence of a particular event. Here the event is the word used to describe any particular set of the outcome. For Example, when a coin is tossed the total number of possible outcomes are 2 i.e {Head, Tail}. And the probability of getting head, P(Head) is 1/2. since the number of success for getting head is 1.
P(A and B) or P(A ∩ B) = P(A)·P(B) P(A or B) = P(A) + P(B) - P(A and B)Example-1: Tokens numbered 1 to 20 are mixed up and then a token is drawn at random. What is the probability that the token drawn has a number which is a multiple of 3 or 5? Solution: Total possible outcome,
S = {1, 2, 3, 4, 5, ...20} The favorable outcome, which is multiple of 3 or 5 is
E = {3, 6, 9, 12, 15, 18, 5, 10, 20} Then,
P(E) = n(E)/ n(S) where n(E) represents number of favorable outcome
P(E) = 9/20 Example-2: An Urn contains 2 red, 3 green, and 5 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue? Solution:
Total number of ball = 10, Number of blue ball = 5
P(Blue) = Number of blue balls / total number of balls
P(Blue) = 5/10 = 1/2
P(not blue) = 1 - P(Blue)
P(not blue) = 1- 1/2 = 1/2
Example-3: Find the probability of getting sum more that 7, when we simultaneously throw a pair of dice. Solution: Total number of outcome,
= 62 = 36
Number of favorable outcome,
= {(2, 6)
(3, 5) (3, 6)
(4, 4) (4, 5) (4, 6)
(5, 3) (5, 4), (5, 5) (5, 6)
(6, 2) (6, 3) (6, 4) (6, 5) (6, 6)} = 15
P(sum more than 7) = 15/36 = 5/12
Example-4: Find the probability of getting two consecutive Heads when three coins are tossed simultaneously. Solution:
Total number of outcome,
= 23 = 8
These are,
{(HHH), (HTH), (HHT), (HTT), (THH), (THT), (TTH), (TTT)}
Number of favorable outcome,
= {(HHH), (HHT), (THH)} = 3
P(getting two consecutive heads) = 3/8