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Java long compareTo() with examples

Last Updated : 5 Dec, 2018
The java.lang.Long.compareTo() is a built-in method in java that compares two Long objects numerically. This method returns 0 if this object is equal to the argument object, it returns less than 0 if this object is numerically less than the argument object and a value greater than 0 if this object is numerically greater than the argument object. Syntax:
public int compareTo(Object obj)

Parameter: 
obj - The object which is to be compared to.
Returns: The function returns three values:
  • equal to 0: Object is equal to the argument object
  • less than 0: Object is less than the argument object
  • greater than 0: Object is greater than the argument object
Program 1: The program below demonstrates the working of function. Output:
object1 is less than object2
Program 2: The program below demonstrates the working of function when no argument is passed Output:
prog.java:14: error: method compareTo in class Long cannot be applied to given types;
 int compareValue = obj1.compareTo(); 
 ^
 required: Long
 found: no arguments
 reason: actual and formal argument lists differ in length
1 error
Program 3: The program below demonstrates the working of function when anything other than object is passed in an argument
Output:
prog.java:14: error: incompatible types: String cannot be converted to Long
 int compareValue = obj1.compareTo("gfg"); 
 ^
Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output
1 error
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